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Paha777
1 month ago
7

Fourteen runners in a marathon had these race times, in hours,

Mathematics
1 answer:
AnnZ [12.3K]1 month ago
7 0

Answer:

Attached is the histogram illustrating the marathon runners’ times.

Step-by-step explanation:

The provided data is as follows;

2.21

2.25

2.76

3.1

3.3

3.5

3.6

3.77

3.8

4.23

4.25

4.25

4.6

4.9

From this data, we can determine;

The count of runners finishing between 0 and 1 hour = 0

The count of runners finishing between 1 and 2 hours = 0

The count of runners finishing between 2 and 3 hours = 3

The count of runners finishing between 3 and 4 hours = 6

The count of runners finishing between 4 and 5 hours = 5

Based on these frequencies across the various time ranges, the histogram for the provided data has been constructed and is attached.

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The formula F=9/5(k-273.15)+32 converts a temperature from kelvin K to degrees Fahrenheit F.
Svet_ta [12734]

Step One

Deduct 32 from both sides.

F - 32 = \frac{9}{5}(k - 273.15)

Step Two

Multiply each side by \frac{5}{9}.

\frac{5}{9}(F - 32) = \frac{5}{9} \times \frac{9}{5}(k - 273.15)

\frac{5}{9}(F - 32) = k - 273.15

Step Three

Add 273.15 to both sides.

\frac{5}{9}(F - 32) + 273.15 = k

Problem B

F = 180

Solve for k

k = \frac{5}{9}(F - 32) + 273.15

k = \frac{5}{9}(180 - 32) + 273.15

k = \frac{5}{9} \times 148 + 273.15

k = 82.2222 + 273.15

k = 355.3722

k = 355.4  <<< Answer

6 0
2 months ago
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The perimeter of the norwegian flag is 190 inches. What are the dimensions of the flag?
zzz [12365]
<span>The flag's dimensions are 40 inches by 55 inches.

Reasoning<span>:
The perimeter equals the sum of all sides. Being rectangular, opposite sides have equal lengths. Thus, the equation is
y + 11/8 y + y + 11/8 y = 190.

Simplifying, we get
2y + 22/8 y = 190.

Expressing 22/8 as a mixed fraction results in
2y + 2 3/4 y = 190.

Combining terms: 4 3/4 y = 190.

Divide both sides by 4 3/4:
y = 190 ÷ 4 3/4.

Converting 4 3/4 to an improper fraction: y = 190 ÷ 19/4.

Dividing by a fraction means multiplying by its reciprocal:
y = 190 × 4/19 = 760/19 = 40.

Since y = 40, calculate 11/8 y = 11/8 × 40 = 440/8 = 55.</span></span>
8 0
2 months ago
Yao Xin puts 3/10 liters of potting soil in each pot for planting flowers. She has 17/3 liters of potting soil. How many pots ca
babunello [11817]

In this scenario, we'll define the following variables:

x: total volume of potting soil in liters.

y: quantity of potting soil allocated to each pot in liters.

To determine the number of pots, we can use the expression:

N = \frac{x}{y}

Substituting in the respective values yields:

N = \frac{\frac{17}{3}}{\frac{3}{10}}

Reformatting gives us:

N = \frac{170}{9}

N = 18.8

When rounding down to the nearest whole number, we find:

N = 18

The conclusion is:

Yao Xin is capable of filling 18 pots.

4 0
1 month ago
cynara has a bag of red, blue, and black pens. She randomly selects a pen, records the color, and puts it back in the bag, She d
lawyer [12517]

Calculate the probability of each pen color by dividing the number of times each color was chosen by the total selections:

Red pens: 6 out of 30, which simplifies to 1/5

Blue pens: 10 out of 30, which simplifies to 1/3

Black pens: 14 out of 30, which simplifies to 7/15

To find the likelihood of first selecting a blue pen and then a red pen, multiply their individual probabilities:

(1/3) × (1/5) = 1/15

The resulting probability is 1/15.

1 0
2 months ago
A bag contains chips of which 27.5 percent are blue. A random sample of 5 chips will be selected one at a time and with replacem
lawyer [12517]

Answer:

\mu _{\hat{p}}= 0.275\\\\ \sigma_{\hat{p}}=0.1997

Step-by-step explanation:

It is known that the mean and standard deviation of the sampling distribution of the sample proportion(\hat{p}) are represented as follows:-

\mu _{\hat{p}}=p\\\\ \sigma_{\hat{p}}=\sqrt{\dfrac{p(1-p)}{n}}

, where p= Population proportion and n = sample size.

Let p denote the proportion of blue chips.

According to the information provided, we have

p= 0.275

n= 5

Thus, the mean and standard deviation of the sampling distribution of the sample proportion of blue chips for samples of size 5 will be:

\mu _{\hat{p}}= 0.275\\\\ \sigma_{\hat{p}}=\sqrt{\dfrac{ 0.275(1- 0.275)}{5}}\\\\=0.19968725547\approx0.1997

Therefore, you will have the mean and standard deviation for the sample proportion of blue chips for samples of size 5:

\mu _{\hat{p}}= 0.275\\\\ \sigma_{\hat{p}}=0.1997

6 0
22 days ago
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