Step One
Deduct 32 from both sides.
F - 32 = \frac{9}{5}(k - 273.15)
Step Two
Multiply each side by \frac{5}{9}.
\frac{5}{9}(F - 32) = \frac{5}{9} \times \frac{9}{5}(k - 273.15)
\frac{5}{9}(F - 32) = k - 273.15
Step Three
Add 273.15 to both sides.
\frac{5}{9}(F - 32) + 273.15 = k
Problem B
F = 180
Solve for k
k = \frac{5}{9}(F - 32) + 273.15
k = \frac{5}{9}(180 - 32) + 273.15
k = \frac{5}{9} \times 148 + 273.15
k = 82.2222 + 273.15
k = 355.3722
k = 355.4 <<< Answer
<span>The flag's dimensions are 40 inches by 55 inches.
Reasoning<span>:
The perimeter equals the sum of all sides. Being rectangular, opposite sides have equal lengths. Thus, the equation is
y + 11/8 y + y + 11/8 y = 190.
Simplifying, we get
2y + 22/8 y = 190.
Expressing 22/8 as a mixed fraction results in
2y + 2 3/4 y = 190.
Combining terms: 4 3/4 y = 190.
Divide both sides by 4 3/4:
y = 190 ÷ 4 3/4.
Converting 4 3/4 to an improper fraction: y = 190 ÷ 19/4.
Dividing by a fraction means multiplying by its reciprocal:
y = 190 × 4/19 = 760/19 = 40.
Since y = 40, calculate 11/8 y = 11/8 × 40 = 440/8 = 55.</span></span>
In this scenario, we'll define the following variables:
x: total volume of potting soil in liters.
y: quantity of potting soil allocated to each pot in liters.
To determine the number of pots, we can use the expression:
Substituting in the respective values yields:
Reformatting gives us:
When rounding down to the nearest whole number, we find:
The conclusion is:
Yao Xin is capable of filling 18 pots.
Calculate the probability of each pen color by dividing the number of times each color was chosen by the total selections:
Red pens: 6 out of 30, which simplifies to 1/5
Blue pens: 10 out of 30, which simplifies to 1/3
Black pens: 14 out of 30, which simplifies to 7/15
To find the likelihood of first selecting a blue pen and then a red pen, multiply their individual probabilities:
(1/3) × (1/5) = 1/15
The resulting probability is 1/15.
Answer:

Step-by-step explanation:
It is known that the mean and standard deviation of the sampling distribution of the sample proportion(
) are represented as follows:-

, where p= Population proportion and n = sample size.
Let p denote the proportion of blue chips.
According to the information provided, we have
p= 0.275
n= 5
Thus, the mean and standard deviation of the sampling distribution of the sample proportion of blue chips for samples of size 5 will be:

Therefore, you will have the mean and standard deviation for the sample proportion of blue chips for samples of size 5:
