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pychu
5 days ago
10

The weights of soy patties sold by Veggie Burgers Delight are normally distributed. A random sample of 15 patties yields a mean

weight of 3.8 ounces with a sample standard deviation of 0.5 ounces. At the 0.05 level of​ significance, perform a hypothesis test to see if the true mean weight is less than 4 ounces. The correct calculated value of the test statistic is​ _______.
Mathematics
1 answer:
Svet_ta [4.3K]5 days ago
3 0

Answer:

t=\frac{3.8-4}{\frac{0.5}{\sqrt{15}}}=-1.549

Step-by-step explanation:

Given data and notation

\bar X=3.8 indicates the sample mean

s=0.5 refers to the sample standard deviation

n=15 is the sample size

\mu_o =4 represents the value we are testing.

\alpha indicates the significance level for the hypothesis test.

t refers to the statistic of interest.

p_v is the p-value for the test (the variable we are interested in).

Formulate the null and alternative hypotheses.

I will set up the hypotheses to verify if the mean weight falls below 4 ounces, formalizing:

Null hypothesis: \mu \geq 68

Alternative hypothesis: \mu < 4

Since our sample size is < 30 and the population standard deviation is unknown, it’s advisable to utilize a t test to compare the actual mean against the reference value, with the statistic calculated as follows:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)

t-test: "This test compares group means and is commonly utilized to determine if the mean is (greater than, less than, or not equal to) a specific value."

Calculate the statistic

We can substitute the provided information into formula (1):

t=\frac{3.8-4}{\frac{0.5}{\sqrt{15}}}=-1.549 

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