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Naya
11 days ago
15

How many calories will Darrel burn in 1 minute while kayaking enter the answer below in the box 50/200, 100/400, 150/600, 200/80

0
Mathematics
1 answer:
Zina [3.9K]11 days ago
8 0

Response: 100/400

Detailed explanation:

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Liam cuts a 48-inch piece of string into two pieces. One piece is 12 inches longer than the other. If s represents the length of
Inessa [3926]

Answer:

Here is the solution to the entire assessment: https://school.ckseattle.org/documents/2019/2/8_2_The_Pythagorean_Theorem_and_Its_Converse.pdf

Step-by-step explanation:

4 0
3 days ago
If ABCD is a parallelogram, which of the following statements must be true?
lawyer [4039]

Answer: d. AB = CD and BC = AD


Step-by-step explanation:

A parallelogram is defined as a four-sided figure with the following characteristics:-

  1. Opposite sides are equal (AB = CD and BC = AD ).
  2. Opposite angles are equal (∠A=∠C and ∠D=∠B).
  3. Consecutive angles are supplementary (∠A + ∠D = 180°).
  4. The diagonals bisect one another.
  5. If one angle is a right angle, then all angles are right angles.

8 0
6 days ago
Read 2 more answers
Line GH contains points G(–2, 6) and H(5, –3). What is the slope of ?
PIT_PIT [3949]

We apply the slope formula by substituting the given points.

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

Here, x2 equals 5 and x1 equals -2; y2 equals -3 and y1 equals 6.

m=\frac{-3-6}{5-(-2)}=\frac{-9}{7}

Thus, the line's slope is -9 divided by 7.

5 0
15 days ago
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The First Lady planted rhubarb in the square bed above. Express the perimeter of the rhubarb bed in the terms of x.
babunello [3666]

Response:

......

Detailed explanation:

7 0
9 hours ago
A rocket was launched into the air from a podium 6 feet off the ground. The rocket path is represented by the equation h(t)=-16t
lawyer [4039]

Answer:

60

Step-by-step explanation:

The function provided is:

h(t)=-16t^2+120t+6

The average rate of change of h(t) as time goes from t=a to t=b is expressed as:

\frac{h(b)-h(a)}{b-a}

This function can be reformulated as: h(t)=-16(t-3.75)^2+231

The rocket's peak height is 231, which occurs at t=3.75 seconds.

\implies h(3.75)=231

The initial launch happens at: t=0

and h(0)=-16(0)^2+120(0)+6=6

The average rate of change from launch to max height is

\frac{h(3.75)-h(0)}{3.75-0}=\frac{231-6}{3.75-0} =60

6 0
8 days ago
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