Lea and Marie are washing all the windows in their house. It would take Lea 80 minutes to wash the windows by herself, and it wo

Answer:

Step-by-step explanation:

Step 1:-

We have c1(t) = e^ t i + (sin(t))j + t³k

and c2(t) = e^−t i + (cos(t))j − 6t³k.

By adding c1(t) and c2(t):

c1(t)+c2(t) = e^ t i + (sin(t))j + t³k + e^−t i + (cos(t))j − 6t³k

Now, employing the derivative formula:

Next, differentiate with respect to 't'

By factoring out i, j, and k terms, we arrive at:

Answer:

a) The distance covered halfway = 16.49 [m], while the displacement at that point = 10.5 [m]b)

The distance traveled increases

when the child finishes one lap around the track.

Step-by-step explanation:

a)

Distance is a scalar measurement

that indicates how much ground an object has traversed in motion. Contrarily, displacement is a vector measurement which describes how far an object is from its original position after moving.

In this scenario, the child travels halfway around the circular track from point 1 to point 2. We know that the circumference or perimeter of a circle can be calculated as 2*PI*radius. Since the child only covers half the distance, we need to divide the circumference by 2, leading to distance = PI*radius

The halfway distance = (PI)*(5.25) = 16.49 [m]

Considering the definition of displacement, it’s clear that the distance from point 1 to point 2 equals one diameter from the starting point:

The halfway displacement = D = 2*radius = 2(5.25) = 10.5 [m]

b) What occurs to the distance after the child completes one full circuit? The distance will increase since the child covers more ground during the full lap:

• The distance for one circuit = 2*(PI)*radius = 2(PI)(5.25) = 32.99 [m]

32.99 is greater than 16.49, confirming that the distance does indeed increase.