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lisabon 2012
1 month ago
8

What is the simplified form of the following expression ? Assume a _>0 and c >_0

Mathematics
2 answers:
tester [12.3K]1 month ago
7 0

Response:

A

Detailed explanation:

tester [12.3K]1 month ago
3 0
14 \sqrt[4]{a^{5} b^{2 }c^{4}} -7ac \sqrt[4]{a b^{2}}
= 14ac \sqrt[4]{a b^{2}} -7ac \sqrt[4]{a b^{2}}
= 7ac \sqrt[4]{a b^{2}}.... pertains to the first choice
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Two ferries travel across a lake 50 miles wide. One ferry goes 5 miles per hour slower than the other. If the slower ferry leave
Svet_ta [12734]

Answer:

Step-by-step explanation:

Let x represent the speed of the first ferry.

Consequently, the second ferry's speed is x-5, as it travels 5 miles per hour slower.

The time taken by the first ferry is calculated as distance divided by speed = \frac{50}{x}

The time taken by the second ferry equals \frac{50}{x-5}.

Since the second ferry departs one hour earlier, the times differ by 1 hour.

\frac{50}{x-5}-\frac{50}{x}=1\\50x-50(x-5)=x(x-5)\\250 = x^2-5x\\x^2-5x-250 =0\\(x-10)(x+5) =0\\x=18.5, -13.5

The speed cannot be negative.

Thus, the speed of the first ferry is determined to be 18.5 mph,

and for the second, slower ferry, it equals 13.5 mph.

5 0
1 month ago
2. José is using 12 brown tiles and
AnnZ [12381]
The answer is: 12:20.
3 0
24 days ago
Rework problem 4 from section 3.2 of your text, involving sets E and F. Suppose for this problem that Pr[E]=1/12, Pr[F]=1/12, an
Inessa [12570]
The corresponding Venn Diagram for this issue is depicted below

P(E|F) and P(F|E) denote the conditional probabilities.

P(E|F) is calculated as P(E∩F) ÷ P(F) = ¹/₂ ÷ ¹/₂ = 1
P(F|E) is determined by P(F∩E) ÷ P(E) = ¹/₂ ÷ ¹/₂ = 1

3 0
1 month ago
number between 1 and 10, inclusive, is randomly chosen. Events A and B are defined as follows. A: {The number is even} B: {The n
Svet_ta [12734]

Answer:

The union of sets A and B is represented as A U B = {1,2,3,4,5,6,8}

Detailed explanation:

We begin by defining our sets.

Let ¢ signify the universal set (which includes every element in the given sets)

¢ = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

A= {2, 4, 6, 8}

B= {1,2,3,4,5,6}

Consequently: A U B (the union of A and B):

A U B = {1, 2, 3, 4, 5, 6, 8}

6 0
14 days ago
What is true about the solution of StartFraction x squared Over 2 x minus 6 EndFraction = StartFraction 9 Over 6 x minus 18 EndF
PIT_PIT [12445]

Answer:

x=\pm\sqrt{3} and these represent genuine solutions.

Step-by-step explanation:

We have

\frac{x^2}{2x-6}=\frac{9}{6x-18}

Factor both sides' denominators.

\frac{x^2}{2(x-3)}=\frac{9}{6(x-3)}

Simplify.

\frac{x^2}{2}=\frac{9}{6}

x^2=\frac{18}{6}

x=\pm\sqrt{3}

Verify

1) For x=\sqrt{3}

\frac{\sqrt{3}^2}{2(\sqrt{3}-3)}=\frac{9}{6(\sqrt{3}-3)}

\frac{3}{2(\sqrt{3}-3)}=\frac{9}{6(\sqrt{3}-3)}

18=18 ---> is valid.

Thus,

x=\sqrt{3} -----> is a legitimate solution.

2) For x=-\sqrt{3}

\frac{-\sqrt{3}^2}{2(-\sqrt{3}-3)}=\frac{9}{6(-\sqrt{3}-3)}

\frac{3}{2(-\sqrt{3}-3)}=\frac{9}{6(-\sqrt{3}-3)}

18=18 ---> is valid.

Therefore,

x=-\sqrt{3} -----> is a legitimate solution.

Thus,

3 0
1 month ago
Read 2 more answers
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