Answer:
- 128 Superscript StartFraction 3 Over x EndFraction
- (4RootIndex 3 StartRoot 2 EndRoot)x
- (4 (2 Superscript one-third Baseline) ) Superscript x
Step-by-step explanation:
Considerando la ecuación dada ![(\sqrt[3]{128} )^{x}\\](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7B128%7D%20%29%5E%7Bx%7D%5C%5C)
De acuerdo con una de las leyes de índices,
![(\sqrt[a]{m} )^{b}\\= (\sqrt{m})^\frac{b}{a}](https://tex.z-dn.net/?f=%28%5Csqrt%5Ba%5D%7Bm%7D%20%29%5E%7Bb%7D%5C%5C%3D%20%28%5Csqrt%7Bm%7D%29%5E%5Cfrac%7Bb%7D%7Ba%7D)
Aplicando esta ley a la pregunta;
![(\sqrt[3]{128} )^{x}\\ = {128} ^\frac{x}{3}\\ \\= (\sqrt[3]{64*2})^{x} \\ = (4\sqrt[3]{2})^{x} \\= (4(2^{1/3} )^{x} )](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7B128%7D%20%29%5E%7Bx%7D%5C%5C%20%3D%20%7B128%7D%20%5E%5Cfrac%7Bx%7D%7B3%7D%5C%5C%20%5C%5C%3D%20%28%5Csqrt%5B3%5D%7B64%2A2%7D%29%5E%7Bx%7D%20%5C%5C%20%3D%20%284%5Csqrt%5B3%5D%7B2%7D%29%5E%7Bx%7D%20%5C%5C%3D%20%284%282%5E%7B1%2F3%7D%20%29%5E%7Bx%7D%20%29)
<pLos siguientes son ciertos de acuerdo con el cálculo presentado
128 Superscript StartFraction 3 Over x EndFraction
(4RootIndex 3 StartRoot 2 EndRoot)x
(4 (2 Superscript one-third Baseline) ) Superscript x
You can easily calculate the result for each segment and then sum them to determine the perimeter of triangle MNK.
The solution to the equation is 75.
Response:
The connection between battery capacity and time is:
The associated graph is provided.
Step-by-step explanation:
We will plot the battery's charged capacity against time.
The charging rate remains steady; hence, the relationship is linear.
Initially, at time t=0, the battery's capacity measures 0.2 (or 20%).
With each passing minute, an additional 5% of its capacity is accumulated. Thus, at t=1, the capacity becomes 0.2 + 0.05 = 0.25 (or 25%).
We can derive the slope for the linear function as:
Consequently, the correlation between battery capacity and time is:
To determine the future value using simple interest, the formula is: future value = present value (1+n*rate), where n represents the number of years and rate indicates the annual interest as a decimal. By substituting the values into the equation, we find that 10000 = 3900(1 + 0.0783*t). Therefore, we calculate 1 + 0.0783t = 10000/3900, leading to t = (10000/3900 - 1)/0.0783, which equals approximately 19.98 years. For compound interest, the future value is determined by present value (1 + rate/n)^(nt), where n=1, rate=0.0783, future value=10000, present value=3900, ultimately resulting in t = log(10000/3900)/log(1.0783) which yields roughly 12.49 years.
