Susan and Jim own a lawn care business. The amount Susan charges for a lawn care by the hour is shown in the table.

Let's consider that Susan's graph represents a linear equation. We can then perform linear interpolation. Let y denote the charge for 10 hours of work:

(7-10)/(7-11) = (168-y)/(168-264)
y = $240

For Jim’s Lawn care, calculate the consistent slope utilizing the points (1,20) and (2,40):

m = (20 - 40)/(1-2) = 20
Since the y-intercept is zero, the resulting linear equation is:
y = 20x
Substituting x = 10 hours yields,[
y = 20(10) = $200

The variance between the two amounts then becomes:
Difference = $240 - $200 = $40