Answer:
Step-by-step explanation:
The probability that a mosquito lands on your neck per second is 0.5
The chance of it biting once it lands is 0.2
The likelihood that it does not bite after landing is 0.8
Therefore, the probability of a bite in one second is
This translates to a 1/100 likelihood of being bitten in just one second
Over the course of 100 seconds, the expected number of bites is
The anticipated interval between bites is 100
Answer:
a) In this case, we have a z-score of 1.57, characterized as:
This signifies that our score is 1.57 standard deviations above the average of all test scores.
b)
Using the normal standard distribution or Excel, we computed:
This represents 2.275% of the dataset.
Step-by-step explanation:
Previous concepts
Normal distribution denotes a "probability distribution that is symmetric around the mean, indicating that data close to the mean occurs more frequently than data further from it".
The Z-score serves as "a statistical measurement representing a value's relation to the average (mean) of a set, calculated in terms of standard deviations away from the mean".
Solution to the problem
Part a
For this instance, we hold a z-score of 1.57, which is defined as:
This shows that our score is 1.57 deviations above the overall test score average.
Part b
A z-score of z=-2 indicates that your friend's score is 2 deviations below the other test scores.
Assuming a normal distribution, we can derive the percentage:
Using the normal standard distribution or Excel, we discovered:
This represents 2.275% of the data.