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otez555
3 months ago
8

A ray of yellow light ( f = 5.09 × 1014 hz) travels at a speed of 2.04 × 108 meters per second in

Physics
1 answer:
inna [3.1K]3 months ago
6 0
Velocity = fλ

where f indicates the frequency in Hz, and λ signifies the wavelength in meters.

<span>2.04 * 10⁸ m/s = 5.09 * 10¹⁴ Hz * λ</span>

<span>(2.04 * 10⁸ m/s) / (5.09 * 10¹⁴ Hz) = λ</span>

<span>4.007*10⁻⁷ m = λ</span>

<span>The wavelength of yellow light is 4.007*10⁻⁷ m<span> </span></span>
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Use the formula t = (0.25) s1/2 to find the time t in seconds it will take a stone to drop a distance s of 200 feet. Round your
inna [3103]

Answer:

The duration, t = 3.53 seconds

Explanation:

The following information is provided:

The equation to calculate the time t is expressed as:

t=(0.25)s^{1/2}...... (1)

Where

s denotes the distance in feet

We are to determine the duration taken by the stone to fall a distance of 200 feet, where s = 200 feet

Substituting the value of s into equation (1) yields:

t=(0.25)\times (200)^{1/2}

t = 3.53 seconds

Thus, the time taken by the object is 3.53 seconds, which provides the required answer.

4 0
3 months ago
Through how many volts of potential difference must an electron, initially at rest, be accelerated to achieve a wave length of 0
kicyunya [3294]
20.7 volts. The mass of an electron is 9.1 x 10⁻³¹ kg, and its wavelength is 0.27 x 10⁻⁹ m. The velocity of the electron can be determined using de Broglie's equation λ mv = h. Substituting the known values, we arrive at v = 2.7 x 10⁶ m/s. The potential difference through which the electron accelerates is noted, with the charge on an electron being 1.6 x 10⁻¹⁹ C. According to the conservation of energy, (0.5) mv² = q ΔV leads to ΔV = 20.7 volts.
4 0
2 months ago
For a projectile, which of the following quantities are constant during the flight: x, y, vx, vy, v, ax, ay? Check all that appl
Yuliya22 [3333]

Response:

C. vx

F. ax

G. ay

Clarification:

The projectile follows a curved trajectory toward the ground, causing changes in x and y positions.

Since there is no external force acting in the x-direction, the acceleration in x remains at zero. Consequently, ax and vx remain unchanged.

The projectile is subject to the force of gravity, directed downwards, leading to an increase in its velocity due to the rise in its y-component.

Meanwhile, the y-component of acceleration remains constant due to gravitational acceleration.

5 0
3 months ago
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