Mrs. Dimitri purchased a case of yogurt cups. Out of every 10 yogurt cups, 6 are strawberry.

Answer:

Robyn's model is logical, while Mark's is illogical.

Step-by-step explanation:

This question doesn't require calculations. What we need to do is analyze each model logically.

Mark's

Mark's representation indicates 20 instead of 2, which signifies that 200 is ten times greater than 20, making it nonsensical.

Robyn's

Robyn's representation displays 2, suggesting that 200 is 100 times greater than 2, which is not only accurate but also reasonable since 100 * 2 equals 200.

Answer:

8 servings

Step-by-step explanation:

At a ratio of 15:1, for each serving that uses 75 grams of rice, it will need 75/15 = 5 grams of spice. With David having 40 grams of spice, he can prepare ...

40 g/(5 g/serving) = 8 servings

Answer:

7 years

Step-by-step explanation:

Suri is 17 years old.

Her cousin's age is c.

Suri's age is stated to be 4 less than 3 times her cousin’s age.

This means we take 3 times her cousin’s age and subtract 4.

17 = 3c - 4

We now need to solve for c, which represents her cousin's age.

Add 4 to each side:

17 + 4 = 3c - 4 + 4

17 + 4 = 3c

21 = 3c

Now divide both sides by 3:

21/3 = 3c/3

7 = c

Thus,

Her cousin is 7 years old.

Response:

Here is the solution to the question:

Detailed Steps:

The following steps will be followed in this task:

• Step 1: Utilize the formulas tab on the sheet where you will apply the function found in the FLG "Function Library group".

• Step 2: Click on the Financial button, then select PMT.
• Step 3: After selecting PMT, input "B3/12" into the rate argument box.
• Step 4: In B4, fill in the Nper argument box with the value found in cell "B2" for the Pv argument box.
• Step 5: Click the OK button to finish.

Answer:

Step-by-step explanation:

a. The variable X represents the height of a Goomba, which follows a normal distribution with a mean of μ= 12 inches and a standard deviation of δ= 6 inches.

To find the probability that a Goomba picked at random has a height between 13 and 15 inches, you express it as:

P(13≤X≤15)

Considering that standard normal probability tables provide cumulative values, you can express this range as the cumulative probability up to 15 minus the cumulative probability up to 13. You'll first need to standardize these variable heights to obtain corresponding Z values:

P(X≤15) - P(X≤13)

P(Z≤(15-12)/6) - P(Z≤(13-12)/6)

P(Z≤0.33) - P(Z≤0.17)= 0.62930 - 0.56749= 0.06181

b. Now we have Y as the variable indicating the height of a Koopa Troopa. This variable also follows a normal distribution, with a mean μ= 15 inches and a standard deviation δ=3 inches.

The query concerns the probability that a Koopa Troopa stands taller than 75% of Goombas.

First step:

You need to determine the height of a randomly chosen Koopa Troopa that exceeds 75% of the Goomba population.

This entails determining the value of X corresponding to the limit below which 75% of the population falls, denoted by:

P(X ≤ b)= 0.75

Step 2:

Search the standard normal distribution for the Z value that has 0.75 beneath it:

Next, you will reverse the standardization to solve for "b"

Z= (b - μ)/δ

b= (Z*δ)+μ

b= (0.674*6)+12

b= 16.044 inches

Step 3:

With the height that identifies a Koopa Troopa taller than 75% of the Goomba population determined, compute the probability of selecting that Koopa Troopa:

P(Y≤16.044)

This time, utilize the Koopa’s average height and standard deviation to find the probability:

P(Z≤(16.044-15)/3)

P(Z≤0.348)= 0.636

The likelihood of randomly selecting a Koopa Troopa that is taller than 75% of Goombas is 63.6%

I hope this information is useful!