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Gelneren
1 month ago
9

If mBC = (9x-53) and mCD = (2x + 45) find mBAD

Mathematics
1 answer:
babunello [11.8K]1 month ago
7 0

Answer:

m\angle BAD=73^o

Step-by-step explanation:

The diagram related to the question is in the attached figure.

Step 1

Determine the value of x

Let:

O ----> denote the center of the circle

It is known that:

Triangle BOC is congruent to Triangle COD

m\angle BOC=arc\ BC ----> due to the central angle

m\angle COD=arc\ CD ----> according to the central angle

m\angle BOC=m\angle COD

Thus:

arc\ BC=arc\ CD

Insert the provided values

(9x-53)^o=(2x+45)^o

Solve for x

9x-2x=45+53\\7x=98\\x=14

Step 2

Calculate the measure of angle BAD

It is known that:

The inscribed angle measures half that of the arc it subtends.

Thus:

m\angle BAD=\frac{1}{2} [arc\ BC+arc\ CD]

arc\ BC=9(14)-53=73^o

arc\ CD=2(14)+45=73^o

Insert values

m\angle BAD=\frac{1}{2} [73^o+73^o]=73^o

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