A customer at a store paid $64 for 3 large candles and 4 small candles. At the same store, a second customer paid $4 more than t
1 answer:
The equations to determine the price in dollars for each large candle, x, and small candle, y are and
.
Detailed explanation:
In this scenario, a customer bought 3 large candles and 4 small candles for a total of $64. Another customer paid $4 more for 1 large candle and 8 small candles at the same store. The prices of large and small candles remain constant. To identify the equations for determining the price in dollars of each large candle (x) and small candle (y), we can see the following:
Let the price of each large candle be x and each small candle be y. Thus,
A customer at a shop paid $64 for 3 large candles and 4 small candles
This results in the equation:
⇒ .....(1)
The second customer at the store paid $4 more than the previous customer for 1 large candle and 8 small candles.
This gives us the equation:
⇒ .......(2)
3(2)-(1) i.e.
⇒
⇒
⇒
Therefore, the equations to calculate the price in dollars for each large candle, x, and small candle, y are and
.
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Answer:
The appropriate answer is 72 + 4 × x 400.
Step-by-step explanation:
Pine Bluff Middle School's dance committee raises $72 from a bake sale and anticipates $4 for each ticket sold for the Spring Fling dance.
The cost of the dance will be $400.
Let x represent the number of tickets the committee could sell.
The total income amounts to 72 + 4 × x.
After paying for the dance, which costs $400, the committee should have some funds remaining.
This leads to the inequality used to ascertain the number of tickets the committee can sell while ensuring they have money left after the dance expense, formulated as:
72 + 4 × x 400.
we have the function
we understand that
In the context of the exponential function represented as
a signifies the initial value
b denotes the base
x represents the exponent
The initial value indicates the function's value when x equals zero
in this scenario
for
the initial value corresponds to the point
thus
the solution is displayed in the accompanying figure
