Answer:
160/1001, 175/1001
Step-by-step explanation:
i) We calculate:
₈C₁ methods to select 1 new camera from a selection of 8
₆C₃ methods to select 3 refurbished cameras from a selection of 8
₁₄C₄ methods to select 4 cameras from the total of 14 cameras
The probability formula is:
P = ₈C₁ ₆C₃ / ₁₄C₄
P = 8×20 / 1001
P = 160 / 1001
P ≈ 0.160
ii) For at most one new camera, it means we want either one new camera or none at all. We've calculated the probability of selecting one new camera already. The probability of not selecting any new camera is equivalent to selecting 4 refurbished cameras:
P = ₆C₄ / ₁₄C₄
P = 15 / 1001
Therefore, the combined probability is:
P = 160/1001 + 15/1001
P = 175/1001
P ≈ 0.175
The options presented are:
(1) division property of equality
(2) factoring the binomial
(3) completing the square
(4) subtraction property of equality
Response: (2) factoring the binomial
Step 1: 
Step 2:![-c = a[x^2+\frac{b}{a} x]](https://tex.z-dn.net/?f=%20%20-c%20%3D%20a%5Bx%5E2%2B%5Cfrac%7Bb%7D%7Ba%7D%20x%5D%20%20%20)
In step 2, 'a' is extracted from 
. Upon factoring out 'a', we divide all terms by 'a', resulting in ![a[x^2+\frac{b}{a} x]](https://tex.z-dn.net/?f=%20%20%20a%5Bx%5E2%2B%5Cfrac%7Bb%7D%7Ba%7D%20x%5D%20%20%20)
.
Step 2 involves the binomial factorization process.
a) This represents a geometric sequence. b) c) The salary at the beginning of the fifth year will be $46,945.21. To clarify, my starting salary is $37,185. Should I receive a 6% raise each year, the salary for the following year will be: $37,185 x 1.06 = $39,416.10. Consequently, the salary after the second year will be: $39,416.10 x 1.06 = $41,781.07. Hence, the salary sequence will look like: $37,185, $39,416.10, $41,781.07, and so forth, demonstrating a consistent ratio of r = 1.06 for each term.
Answer:
12 pencils per package.
Step-by-step explanation:
Details provided:
Ethan purchased 4 packages of pencils.
Number of Packages = 4
Number of pencils shared with friend = 8 pencils
Pencils remaining = 40 pencils
∴Total Number of Pencils = Pencils given to friend + Pencils remaining = 
Total Pencils in each package = 
C. (1,5) The solution represents where two lines intersect.
