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77julia77
9 hours ago
12

Two small diameter, 10gm dielectric balls can slide freely on a vertical channel each carry a negative charge of 1microcoulomb.

find the separation between the balls if the lower ball is restrained from moving.​
Physics
1 answer:
kicyunya [1K]9 hours ago
5 0

Answer:

The separation distance is d = 0.092 \ m

Explanation:

The mass of each ball is m= 10 g = 0.01 \ kg

The negative charge of each ball is q_1 =q_2=q = 1 \mu C = 1 *10^{-6} \ C

Since the lower ball is prevented from moving, it indicates that the net force acting on it equals zero.

This means that the gravitational force exerted on the lower ball balances the electrostatic force, represented as:

F = \frac{kq_1 * q_2}{d}

=> m* g = \frac{kq_1 * q_2}{d}

where k denotes Coulomb's constant, valued at k = 9*10^{9} \ kg\cdot m^3\cdot s^{-4}\cdot A^2..

Thus,

0.01 * 9.8 = \frac{ 9*10^9 *[1*10^{-6} * 1*10^{-6}]}{d}

d = 0.092 \ m

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