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defon
2 hours ago
9

Draw the vector C⃗ =1.5A⃗ −3B⃗ . The length and orientation of the vector will be graded. The location of the vector is not impo

rtant.

Physics
2 answers:
Yuliya22 [1.1K]2 hours ago
7 0
I created the illustration found in the accompanying file.

There are two images included.

The upper one illustrates the impacts of:

- scaling vector A by a factor of 1.5, depicted in red with a dashed line.

- scaling vector B by -3, shown in purple with a dashed line.

The lower image displays the resultant vector: C = 1.5A - 3B.

The approach involves relocating the tail of vector -3B to the tip of vector 1.5A while maintaining the angles.

Next, an arrow is drawn from the tail of 1.5A to the position of -3B after this shift.

The arrow representing the result is vector C, marked with a black dashed line.
 
ValentinkaMS [1.1K]2 hours ago
5 0

Additional details

A vector is a dimensional quantity characterized by both magnitude and direction.

Vectors can be represented by directed segments.

\large{\boxed{\bold{\overrightarrow{A}}}}

Here, the magnitude of a vector is expressed as | a |.

Vectors can be outlined as coordinate pairs indicating their locations within the Cartesian coordinate system:  a (a₁, a₂).

with length \large{\boxed{\bold{|a|\:=\:\sqrt{a_1^2+a_2^2}}}}

Reversing the direction of vector a yields the vector -a, which retains the same magnitude yet points in the opposite direction.

Vector operations encompass adding and subtracting. The addition of vector a and vector b can be accomplished using a triangular method, aligning the start point of vector b with the end of vector a.

The result is achieved by drawing a segment from the beginning of vector a to the end of vector b, which creates a new vector c.

Thus, we have a + b = c.

When you add vector a to the negative of vector b (-b), the equation becomes a + (-b) = a - b.

Multiplying a vector by a scalar (represented as k) transforms it to k | a |.

If k > 0, the new vector points in the same direction as vector a, whereas if k < 0, it goes in the opposite direction.

The problem provides a partial diagram (see attached), and the total vector to find is C = 1.5A - 3B.

Scaling vector A by 1.5 results in a length that is 1.5 times that of vector A and maintains the same direction. Likewise, vector B, affected by -3, has a length that is three times that of vector B but points in the opposite direction. Hence, we derive vector C (refer to attached image) by drawing a line from the starting point of A to the endpoint of B.

Explore further

velocity position

understanding vector components

coherence in vector operations

Keywords: vector, addition, subtraction

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Keith_Richards [1021]

Answer:

Dₓ = -155 sin 23° i + 0 j

Explanation:

The accompanying diagram illustrates the vector.

According to the diagram,

The vector D has an x-component (or horizontal component) expressed as -D sinθ i. Specifically,

Dₓ = -D sin θ i   [The negative sign indicates that D is directed along the negative x-axis]

Where;

D = magnitude of D = 155m

θ = angle of D = 23°

Consequently;

Dₓ = -155 sin 23° i

Since Dₓ signifies the x component, its unit vector, j component holds a value of 0.

<pthus d="" can="" be="" formulated="" in="" terms="" of="" and="" the="" unit="" vectors="" i="" j="" as="" follows="">

Dₓ = -155 sin 23° i + 0 j

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3 0
15 days ago
A hydraulic lift raises a 2000 kg automobile when a 500 N force is applied to the smaller piston. If the smaller piston has an a
kicyunya [1011]

Answer:

The cross-sectional area of the larger piston is 392cm ^{2}[/tex]

Explanation:

To find the solution, we apply the following equation:

Pascal's principle: F=P*A   Formula (1)

F=Force applied to the piston

P: Pressure

A= Area of the piston

Nomenclature:

Fp= Force on the primary piston= 500N

W= weight of the car =m*g=2000kg*9.8m/s2= 19600N

Fs= Force on the secondary piston= W = 19600N

Ap= Primary piston area=10cm^{2} =10*10^{-4}m^{2}

As= Area of the secondary piston=?

Pressure applied on one side is distributed to all liquid molecules since liquids are incompressible.

From equation (1)

P=F/A

Pp=Ps

\frac{Fp}{Ap} = \frac{Fs}{As}

As= \frac{Fs*Ap}{Fp}

As=\frac{19600*10*10^{-4} }{500}

As=0.0392m^{2} =0.0392*10^{4}cm^{2}

As=392cm ^{2}

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Refer to the attached document for the detailed derivation

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13 days ago
A proton (mass = 1.67 10–27 kg, charge = 1.60 10–19 C) moves from point A to point B under the influence of an electrostatic for
serg [1184]

Answer:

20.353125 V

Explanation:

m = Mass of proton = 1.67\times 10^{-27}\ kg

q = Charge of proton = 1.6\times 10^{-19}\ C

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The relationship derived from energy conservation is as follows:

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Provided Data

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where KE represents kinetic energy

PE indicates potential energy

U denotes internal Energy

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