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Degger
12 days ago
8

Which, if any, of the following statements concerning the work done by a conservative force is NOT true? All of these statements

are true. It can always be expressed as the difference between the initial and final values of a potential energy function. None of these statements are true. It is independent of the path of the body and depends only on the starting and ending points. When the starting and ending points are the same, the total work is zero.
Physics
1 answer:
Yuliya22 [1.1K]12 days ago
8 0

Answer:

If the starting and ending points are identical, the overall work equals zero.

Explanation:

Option (D) is correct.

A force is considered conservative when the work performed by it while moving an object from point A to point B does not rely on the path taken and remains consistent across all paths. The work done is determined solely by the initial and final locations of the particle. Thus, when the initial and final positions in a conservative field coincide, the work is said to be zero.

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Mike recently purchased an optical telescope. Identify the part of the electromagnetic spectrum that is closest to the frequency
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The electromagnetic spectrum spans from radio waves to gamma rays. The picture provided illustrates this entire spectrum. However, the optical telescope is limited to observing only the visible spectrum, which ranges from 400 nm to 700 nm. This segment reflects the colors of ROYGBIV, with red exhibiting the highest frequency and violet the lowest frequency.

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21 hour ago
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Simone is walking her dog on a leash. The dog is pulling with a force of 32 N to the right and Simone is pulling backward with a
ValentinkaMS [1149]

Conclusion:

The total net force acting on the objects is 16 N, directed towards the right.

Clarification:

It is stated that,

The force exerted by the dog, F_1 = 32\ N (to the right)

The force exerted by Simone, F_2 = -16\ N (backward)

Here, assume the backward direction is negative and the right direction is positive.

The net force will move in the direction where the larger force is present. The net force can be calculated as:

F=F_1+F_2

F=32+(-16)

F = 16 N

Thus, the net force amounts to 16 N, acting towards the right.

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3 days ago
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1)After catching the ball, Sarah throws it back to Julie. However, Sarah throws it too hard so it is over Julie's head when it r
Softa [913]

Answer:

1)

v_{oy}=11.29\ m/s

2)

y=7.39\ m

Explanation:

Projectile Motion

When an object is projected near the surface of the Earth at an angle \theta to the horizontal, it follows a trajectory known as a parabola. The only force acting on it (ignoring wind resistance) is gravity, affecting the vertical axis.

The height of a projectile can be calculated using

\displaystyle y=y_o+V_{oy}t-\frac{gt^2}{2}

where y_o represents the initial height from ground level, v_{oy} is the vertical component of the initial velocity, and t is the elapsed time.

The vertical speed component is expressed as

v_y=v_{oy}-gt

1) To proceed, we will determine the initial vertical velocity component since we lack sufficient data to calculate the absolute value of v_o.

The peak height is attained when v_y=0, which allows us to compute the time to reach that height.

v_{oy}-gt_m=0

Solving for t_m

\displaystyle t_m=\frac{v_{oy}}{g}

Thus, the maximum height reached is

\displaystyle y_m=y_o+\frac{v_{oy}^2}{2g}

We know this value is equal to 8 meters

\displaystyle y_o+\frac{v_{oy}^2}{2g}=8

Continuing with the calculations for v_{oy}

\displaystyle v_{oy}=\sqrt{2g(8-y_o)}

Substituting known values yields

\displaystyle v_{oy}=\sqrt{2(9.8)(8-1.5)}

\displaystyle v_{oy}=11.29\ m/s

2) At t=1.505 seconds, the ball is positioned above Julie’s head; we can calculate

\displaystyle y=y_o+V_{oy}t-\frac{gt^2}{2}

\displaystyle y=1.5+(11.29)(1.505)-\frac{9.8(1.505)^2}{2}

\displaystyle y=1.5\ m+16,991\ m-11.098\ m

y=7.39\ m

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12 days ago
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Ostrovityanka [942]

Answer:

d) v1 = v2 = v3

Explanation:

This can be determined through the principle of energy conservation. We assess the total mechanical energy E=K+U (the sum of kinetic energy and gravitational potential energy) at both the initial and final positions, ensuring they remain constant.

<pInitially, for the three spheres, we have:

E_i=K_i+U_i=\frac{mv_i^2}{2}+mgh_i=\frac{mv^2}{2}+mgh

Finally, for the three spheres, we see:

E_f=K_f+U_f=\frac{mv_f^2}{2}+mgh_f=\frac{mv_f^2}{2}

<pGiven that E_i=E_f, and since E_i remains identical for all spheres, it follows that E_f is identical for all spheres, indicating that v_f, the final velocity, is equal for each ball.
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Hypothesis: An increase in voltage should result in a corresponding rise in current because according to Ohm's Law,

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