Answer:black
Step-by-step explanation:
You can acquire 42 cookies through 12 different combinations. The first method involves purchasing 2 packs of 21 (21x2 = 42). The second consists of acquiring 1 pack of 21 alongside 3 packs of 7 (21 + 3x7 = 42). The third way is to buy 1 pack of 21 and 21 individual cookies (21 + 21 = 42). The fourth option combines 1 pack of 21, 1 pack of 7, and 14 single cookies (21 + 7 + 14 = 42). The fifth strategy includes 1 pack of 21, 2 packs of 7, and 7 individual cookies (21 + 14 + 7 = 42). The sixth way is to opt for 6 packs of 7 (7x6 = 42). The seventh option is to purchase 5 packs of 7 along with 7 individual cookies (7x5 + 7 = 42). For the eighth method, you can buy 4 packs of 7 and 14 single cookies (7x4 + 14 = 42). The ninth way is to get 3 packs of 7 with 21 single cookies (7x3 + 21 = 42). The tenth consists of acquiring 2 packs of 7 plus 28 individual cookies (7x2 + 28 = 42). The eleventh strategy involves 1 pack of 7 and 35 single cookies (7 + 35 = 42). Lastly, the twelfth method is simply buying 42 individual cookies (42 = 42).
Answer:
The ratio
corresponds to the tangent of ∠I.
Step-by-step explanation:
Let’s revisit the trigonometric ratios:
For triangle HIJ
∵ m∠J = 90°
- The hypotenuse is the side opposite the right angle.
So, HI is the hypotenuse.
∵ HJ = 3 units
∵ IH = 5 units
- We’ll apply the Pythagorean Theorem to solve for HJ.
∵ (HJ)² + (IJ)² = (IH)²
∴ 3² + (IJ)² = 5²
∴ 9 + (IJ)² = 25
- Subtract 9 from both sides.
∴ (IJ)² = 16
- Taking the square root on both sides gives:
∴ IJ = 4 units
To determine the tangent of ∠I, identify the sides that are opposite and adjacent to it.
∵ HJ is opposite to ∠I
∵ IJ is adjacent to ∠I
- Utilizing the rule of tan above:
∴ tan(∠I) = 
∴ tan(∠I) = 
The ratio
indicates the tangent of ∠I.
(4*4*10)*3
160*3=480
(5*3*10)*2
150*2=300
480+300=780 cubic meters
Response:
The area of the shaded part is 42.50 cm².
Detailed explanation:
Examine the diagram provided.
The circle has a radius of r = 5 cm.
Dimensions of the rectangle are:
l = 11 cm
b = 11 cm.
Calculate the area of the shaded portion as follows:
Area of the shaded region = Area of rectangle - Area of circle
![=[l\times b]-[\pi r^{2}]\\\\=[11\times 11]-[3.14\times 5\times 5]\\\\=121-78.50\\\\=42.50](https://tex.z-dn.net/?f=%3D%5Bl%5Ctimes%20b%5D-%5B%5Cpi%20r%5E%7B2%7D%5D%5C%5C%5C%5C%3D%5B11%5Ctimes%2011%5D-%5B3.14%5Ctimes%205%5Ctimes%205%5D%5C%5C%5C%5C%3D121-78.50%5C%5C%5C%5C%3D42.50)
Consequently, the shaded area totals 42.50 cm².