In each instance, when it sheds a shell, its size increases by a factor of 1 1/3. To determine the growth after the first molt, multiply 1 cm by 1 1/3 to get 1 1/3 cm. To find the next size, repeat the multiplication: 1 1/3 cm times 1 1/3 cm equals 16/9. This process will continue by multiplying by 1 1/3. We can express it mathematically as (initial size) * 1 1/3 *(number of shells) equals length or 1 cm * 1 1/3 * n equals L. Given that the final length is 10 cm, accordingly, 1 1/3 * n equals 10 cm, leading to n being 7.5 shells, which translates to either about 7 or 8 shells.
Answer:
3
Step-by-step explanation:
The coach organizes her 9 players into groups of 3. Therefore, she has a total of 9 players and wants to group them in sets of 3.
To determine how many groups of three can be formed, we divide the total players by 3. This gives us:
9 / 3 = 3 groups
Thus, there will be 3 groups of 3 players each.
We need to examine the information about their ages and wording closely.
The initial statement, "Tom is younger than Andy," implies that Andy is older than Tom. This means Andy ranks before Tom in age. Assigning ranks, Andy = 1 (oldest) and Tom = 2.
The following statement, "John is not older than Tom," indicates John must be younger than or the same age as Tom, so John is younger. Consequently, John is the youngest, ranked 3.
Putting them in order from the youngest to oldest: John (3), Tom (2), Andy (1).
In summary, the age sequence from youngest to oldest is John, Tom, then Andy.
Response:
(i) 15 m, 6 m/s
(ii) 90 m
Detailed explanation:
(i) For a certain acceleration (a) starting from rest, the distance traveled (d) at time t is expressed as...
d = (1/2)at^2
The distance Ben covers in the 5 seconds of acceleration is...
d = (1/2)(1.2 m/s²)(5 s)² = 15 m
Additionally, Ben’s velocity at this instant is...
s = (1.2 m/s²)(5 s) = 6 m/s
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(ii) After 5 seconds of walking by Ben, Alan has walked for 10 seconds, accumulating distance (10 s)(4 m/s) = 40 m. The distance difference between them of 40 - 15 = 25 m is being closed at the rate of their speed difference: (6 m/s) -(4 m/s) = 2 m/s.
It will take an additional (25 m)/(2 m/s) = 12.5 s for Ben to catch up to Alan. In the total of 22.5 s during which Alan has been moving before they reunite, he will have traveled...
(22.5 s)(4 m/s) = 90 m... which is the distance OP