Part 1: Calculate the lateral area of the cone. Part 2: Determine the lateral surface area of the cylinder. Part 3: Assess the surface area of the crayon. For Part 1, we need to find the lateral area of the cone. It equals... For Part 2, to find the lateral surface area of the cylinder... For Part 3, the crayon's surface area sums the lateral areas of both shapes and the areas of the top and bottom surfaces.
Positioning a 45-foot ladder against a building that is 36 feet tall, how far from the base of the building will the bottom of the ladder rest?
Answer:
3) A line has one dimension, length. (True)
5) A plane is made up of an infinite collection of lines. (True)
Explanation:
Geometry has three undefined terms:
a) point
b) line
c) plane
Examining the given statements:
1) A point described as (x, y) has two dimensions — this is incorrect because a point has no dimensions.
2) A plane has clear start and end points — this is false as a plane extends infinitely without boundaries.
3) A line has exactly one dimension, which is its length. (True)
4) A point consists of countless lines — this is false; actually, a line consists of infinite points.
5) A plane consists of an unending set of lines. (True)
Respuesta:
(a) 4.98x10⁻⁵
(b) 7.89x10⁻⁶
(c) 1.89x10⁻⁴
(d) 0.5
(e) 2.9x10⁻²
Explicación paso a paso:
La probabilidad (P) de encontrar la partícula está dada por:
(1)
La solución de la integral de la ecuación (1) es:
(a) La probabilidad de encontrar la partícula entre x = 4.95 nm y 5.05 nm es:
(b) La probabilidad de encontrar la partícula entre x = 1.95 nm y 2.05 nm es:
(c) La probabilidad de encontrar la partícula entre x = 9.90 nm y 10.00 nm es:
(d) La probabilidad de encontrar la partícula en la mitad derecha de la caja, es decir, entre x = 0 nm y 50 nm es:
![P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{0}^{50.00} = 0.5](https://tex.z-dn.net/?f=%20P%3D%5Cfrac%7B2%7D%7B100%7D%20%5B%5Cfrac%7BX%7D%7B2%7D%20-%20%5Cfrac%7BSin%282%5Cpi%20x%2F100%29%7D%7B4%5Cpi%20%2F100%7D%5D%7C_%7B0%7D%5E%7B50.00%7D%20%3D%200.5%20)
(e) La probabilidad de encontrar la partícula en el tercio central de la caja, es decir, entre x = 0 nm y 100/6 nm es:
Espero que te ayude.