answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ANEK
1 month ago
8

The bus routes in a city run on average every 15 minutes. The route times can vary by three minutes. Which absolute value equati

on can be used to find the maximum and minimum wait times at a bus stop?
Mathematics
1 answer:
AnnZ [12.3K]1 month ago
3 0

Response:

Max = 18\ mins

Min = 12\ mins

Step-by-step explanation:

Information given:

Time = 15\ mins

Variation = 3\ mins

Objective:

Calculate the maximum and minimum values

The max value is found as follows:

Max = Time + Variation

Max = 15\ mins + 3\ mins

Max = 18\ mins

The min value is identified as follows:

Min = Time - Variation

Min = 15\ mins - 3\ mins

Min = 12\ mins

You might be interested in
A jumbo crayon is composed of a cylinder with a conical tip. The cylinder is 12 cm tall with a radius of 1.5 cm, and the cone ha
babunello [11817]
Part 1: Calculate the lateral area of the cone. Part 2: Determine the lateral surface area of the cylinder. Part 3: Assess the surface area of the crayon. For Part 1, we need to find the lateral area of the cone. It equals... For Part 2, to find the lateral surface area of the cylinder... For Part 3, the crayon's surface area sums the lateral areas of both shapes and the areas of the top and bottom surfaces.
8 0
18 days ago
Read 2 more answers
If you place a 45-foot ladder against the top of a 36-foot building, how many feet will the bottom of the ladder be from the bot
tester [12383]
Positioning a 45-foot ladder against a building that is 36 feet tall, how far from the base of the building will the bottom of the ladder rest?

4 0
1 month ago
Which statements are true regarding undefinable terms in geometry? Select TWO options
PIT_PIT [12445]

Answer:

3) A line has one dimension, length. (True)

5) A plane is made up of an infinite collection of lines. (True)

Explanation:

Geometry has three undefined terms:

a) point

b) line

c) plane

Examining the given statements:

1) A point described as (x, y) has two dimensions — this is incorrect because a point has no dimensions.

2) A plane has clear start and end points — this is false as a plane extends infinitely without boundaries.

3) A line has exactly one dimension, which is its length. (True)

4) A point consists of countless lines — this is false; actually, a line consists of infinite points.

5) A plane consists of an unending set of lines. (True)

7 0
2 months ago
A square lot has sides of 39.875 m<br> Which is the best estimate for the perimeter of the lot?
PIT_PIT [12445]
b
4 0
24 days ago
The ground-state wave function for a particle confined to a one-dimensional box of length L is Ψ=(2/L)^1/2 Sin(πx/L). Suppose th
AnnZ [12381]

Respuesta:

(a) 4.98x10⁻⁵

(b) 7.89x10⁻⁶

(c) 1.89x10⁻⁴

(d) 0.5

(e) 2.9x10⁻²

Explicación paso a paso:

La probabilidad (P) de encontrar la partícula está dada por:

P=\int_{x_{1}}^{x_{2}}(\Psi\cdot \Psi) dx = \int_{x_{1}}^{x_{2}} ((2/L)^{1/2} Sin(\pi x/L))^{2}dx  

P = \int_{x_{1}}^{x_{2}} (2/L) Sin^{2}(\pi x/L)dx     (1)

La solución de la integral de la ecuación (1) es:

P=\frac{2}{L} [\frac{X}{2} - \frac{Sin(2\pi x/L)}{4\pi /L}]|_{x_{1}}^{x_{2}}  

(a) La probabilidad de encontrar la partícula entre x = 4.95 nm y 5.05 nm es:

P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{4.95}^{5.05} = 4.98 \cdot 10^{-5}    

(b) La probabilidad de encontrar la partícula entre x = 1.95 nm y 2.05 nm es:

P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{1.95}^{2.05} = 7.89 \cdot 10^{-6}  

(c) La probabilidad de encontrar la partícula entre x = 9.90 nm y 10.00 nm es:

P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{9.90}^{10.00} = 1.89 \cdot 10^{-4}    

(d) La probabilidad de encontrar la partícula en la mitad derecha de la caja, es decir, entre x = 0 nm y 50 nm es:

P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{0}^{50.00} = 0.5

(e) La probabilidad de encontrar la partícula en el tercio central de la caja, es decir, entre x = 0 nm y 100/6 nm es:

P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{0}^{16.7} = 2.9 \cdot 10^{-2}

Espero que te ayude.

3 0
25 days ago
Other questions:
  • At what point of the curve y = cosh(x) does the tangent have slope 3?
    7·1 answer
  • Model Exponential Growth Question :A sample of bacteria is growing at a continuously compounding rate. The sample triples in 10
    9·1 answer
  • V=s^2+1/2sh solve for h
    10·1 answer
  • Tristan is 6 years older than Janiyah. The product of their ages 5 years from now will be 187. Whats Janiyahs age
    11·1 answer
  • Which pair of undefined terms is used to define a ray?
    10·2 answers
  • A police car's siren operates at a frequency of 2,000 Hz. What frequency would a stationary listener observe if the police car i
    6·1 answer
  • Deluxe River Cruises operates a fleet of river vessels. The fleet has two types of vessels: A type-A vessel has 60 deluxe cabins
    9·1 answer
  • A wise old owl climbed up a tree whose height was exactly ninety plus three. Every day the owl climbed up 18 and every night cli
    6·1 answer
  • In 2012, Gallup asked participants if they had exercised more than 30 minutes a day for three days out of the week. Suppose that
    7·1 answer
  • Which equation is the inverse of (x minus 4) squared minus two-thirds = 6y minus 12?
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!