6 clients are throwing a party. Each cake serves 24 servings and has a party of 70 +3staff how many cakes are needed?
2 answers:
Answer:
To serve 73 staff members, a total of 3 cakes is necessary.
Detailed explanation:
Given: 6 clients are hosting a party. Each cake can serve 24 people, and there are 70 attendees plus 3 staff members.
To determine: How many cakes are required?
Solution:
Each cake serves 24 individuals, meaning that 1 cake serves 24 people.
For 1 person, it equates to cake.
The entire party consists of 70+3 = 73 individuals.
Thus, 73 people require cakes.
Therefore, 3.04 cakes are needed for 73 individuals.
In conclusion, approximately 3 cakes are needed to cater to 73 staff members.
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Define the unit vectors along the x and y axes as 
correspondingly.
Consequently, the vector from P to Q is
In terms of components, vector PQ is represented as (-8,5).
The magnitude of vector PQ can be calculated as
√[(-8)² + 5²] = √(89) = 9.434
Answer:
Thus, vector PQ is (-8, 5), and its magnitude equals √89 (or 9.434).
Consequently, the vector from P to Q is
In terms of components, vector PQ is represented as (-8,5).
The magnitude of vector PQ can be calculated as
√[(-8)² + 5²] = √(89) = 9.434
Answer:
Thus, vector PQ is (-8, 5), and its magnitude equals √89 (or 9.434).
Begin by disregarding the inequality symbol and substituting it with an '=' sign. After that, determine the x- and y-intercepts.
15x + 10y = 1,100
x-intercept:
15x + 0 = 1,100
x = 1,100/15 = 73.33
y-intercept:
0 + 10y = 1,100
y = 1,100/10 = 110
Now, plot the points (73.33,0) and (0,110). Given that the inequality symbol is ≥, representing equality, connect these points using a solid line.
Next, let's identify a point on the graph, for instance, the origin (0,0). Use this point in the equation.
15x + 10y ≥ 1,100
15(0) + 10(0)? 1,100
0? 1,100
0 < 1,100
This makes the ≥ statement false. As a result, the alternate area defined by the line is the solution. Consequently, shade that region. The resulting graph is displayed in the attached image.
