There are several possible outcomes. The initial composition of the urns is as follows: Urn 1 contains 2 red chips and 4 white chips, totaling 6 chips, whereas Urn 2 has 3 red and 1 white, amounting to 4 chips. When a chip is drawn from the first urn, the probabilities are as follows: for a red chip, it is probability is (2 red from 6 chips = 2/6 = 1/2); for a white chip, it is (4 white from 6 chips = 4/6 = 2/3). After the chip is transferred to the second urn, two scenarios can arise: if the chip drawn from the first urn is white, then Urn 2 will contain 3 red and 2 white chips, making a total of 5 chips, creating a 40% chance for drawing a white chip. Conversely, if a red chip is drawn first, Urn 2 will contain 4 red and 1 white chip, which results in a 20% chance of drawing a white chip. This scenario exemplifies a dependent event, as the outcome hinges on the type of chip drawn first from Urn 1. For the first scenario, the combined probability is (the probability of drawing a white chip from Urn 1) multiplied by (the probability of drawing a white chip from Urn 2), equaling 26.66%. For the second scenario, the probabilities yield a value of 6%.
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Marco requires $420 to purchase a new smartphone along with accessories. The equation 75-495=420 demonstrates this while adding $75 to $420 yields a total of $495.
Answer:
Possible values for X include;
15, 30, 45, 60, and so on
Step-by-step explanation:
The parameters provided are
Number of chocolates Tanmay possessed = X
Number of chocolates given to Akash = 1/3 × X
Number of chocolates given to Sharad = 1/5 × X
Consequently, since both 3 and 5 divide X,
3 × 5 = 15 is the smallest single factor of X.
Thus, the values of X based on this minimum factor are as follows;
15 × 1 = 15
15 × 2 = 30
15 × 3 = 45
15 × 4 = 60
Therefore, potential values for X form an arithmetic series: a + (n - 1) × d
Where:
a = 15
n = 1, 2, 3, 4,...
d = 15
This results in;
15, 30, 45, 60