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Bogdan
2 months ago
6

isco Fever is randomly found in one half of one percent of the general population. Testing a swatch of clothing for the presence

of polyester is 99% effective in detecting the presence of this disease. The test also yields a false-positive in 4% of the cases where the disease is not present. What is the probability that the test result comes back negative if the disease is present
Mathematics
1 answer:
Svet_ta [12.7K]2 months ago
5 0

Answer:

0.8894 represents the likelihood of a negative test result given that the disease is present.

Step-by-step explanation:

We are provided the following in the question:

P(Disco Fever) = P( Disease) =

P(D) = \dfrac{1}{2}\times 1\% = 0.5 \times 0.01 = 0.005

Thus, we can express:

P(No  Disease) =

P(ND) =1 - P(D)= 0.995

P(Test Returns Positive with disease present) = 0.99

P(TP | D ) = 0.99

P( false-positive) = 4%

P( TP | ND) = 0.04

We need to assess the likelihood of a negative test result when the disease is indeed present, i.e.,

P(test result being negative while disease is present)

According to Bayes's theorem, we can write:

P(ND|TP) = \dfrac{P(ND)P(TP|ND)}{P(ND)P(TP|ND) + P(D)P(TP|D)}\\\\P(ND|TP) = \dfrac{0.995(0.04)}{0.995(0.04) + 0.005(0.99)} = 0.8894

0.8894 is the probability that the test result returns negative when the disease exists.

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Assume that 12 people, including the husband and wife pair, apply for 4 sales positions. People are hired at random.
Inessa [12570]

The formula C(n, r)= \frac{n!}{r!(n-r)!}, where r! is defined as 1*2*3*...r

provides the total number of combinations for forming groups of r items from a collection of n items.

For instance, with 10 items, there are C(10,6) possible ways to create groups of 6 from these 10 objects.

-----------------------------------------------------------------------------------------------


Choosing 4 individuals from a total of 12 can be accomplished in:

\displaystyle{C(12, 4)= \frac{12!}{4!8!}= \frac{12\cdot11\cdot10\cdot9\cdot8!}{4!8!}= \frac{12\cdot11\cdot10\cdot9}{4!}=11\cdot5\cdot9= 495 many different ways.


All unique groupings of 4 individuals, including the husband and wife pair, can be computed as C(10, 2) ways, since we only consider the potential selections of 2 from 10 individuals to form a group of 4.


\displaystyle{ C(10, 2)= \frac{10!}{2!8!}= \frac{10\cdot9}{2}=45


Consequently, the probability that both the husband and wife are selected is 45/495=0.09


Part 2)

The chance that one gets selected while the other does not =

P(husband selected, wife not selected) + P(wife selected, husband not selected)

These two scenarios are precisely equal, so it suffices to compute one.


Let's analyze the scenario: husband chosen, wife not selected.

Assuming the husband is selected, we need to determine the possible formations of 3 from the 11 total excluding the wife=10 individuals.

This results in:

\displaystyle{ C(10, 3)= \frac{10!}{3!7!}= \frac{10 \cdot9 \cdot8}{3\cdot2}=10\cdot3\cdot4=120


Hence,


P(husband selected, wife not selected)=120/495=0.24


Thus, the overall probability that one is picked while the other is not =

P(husband selected, wife not selected) + P(wife selected, husband not selected) =

0.24+0.24=0.48



Result:


A) 0.09


B) 0.48

4 0
3 months ago
Tanisha lives with her older sister and helps with the rent by paying $500 per month. Her annual salary as a child care special
AnnZ [12381]

The answer is: Option 'B' is the right choice.

Detailed breakdown:

Her annual income totals $14,700

Her monthly earnings would then be

\dfrac{14700}{12}=\$1225

She desires to buy new items after covering her expenses and saving for her college education.

Based on the provided options:

Only Budgets B and D appear to reflect the correct monthly income, which is $1,225.

In Budget B,

The total savings amount to $400

In Budget D,

The total savings also amount to $400

Thus, Budget B is optimal for achieving her objectives.

As a result, Option 'B' is the correct choice.

4 0
1 month ago
Read 2 more answers
9. Your mathematics instructor claims that, over the years, 88% of his students have said that math is their favorite class. In
tester [12383]

Response:

Step-by-step breakdown:

For the null hypothesis,

H0: p = 88

For the alternative hypothesis,

Ha: p < 88

In terms of population proportion, where the probability of success is p = 0.88

q represents the probability of failure = 1 - p

q = 1 - 0.88 = 0.12

Considering the sample,

Sample proportion, P = x/n

Where

x = number of successes = 21

n = total samples = 32

P = 21/32 = 0.66

Next, we determine the test statistic, which represents the z-score

z = (P - p)/√pq/n

z = (0.66 - 0.88)/√(0.88 × 0.12)/32 = - 3.83

The relevant p-value corresponds by referencing the normal distribution table for the area falling beneath the z-score. As a result,

P value = 0.00006

8 0
1 month ago
A manufacturer of a certain brand of appliance estimates that he can sell 5000 units a year at Php 900.00 each and that he can s
lawyer [12517]

To start, calculate the return for each price per unit

Return = quantity sold x price per unit

Return1 = 5000 units x Php 900

Return1 = Php 4,500,000

Next, figure out the return for the other price per unit

Return2 = quantity sold x price per unit

Return2 = (5000 + 1500 units) x ( Php 900 – 100)

Return2 = Php 5,200,000

Thus, a price of Php 800 per unit will result in a higher return.

8 0
2 months ago
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A CD has a 5% chance of being a smash hit and profiting $5.2 million, a 50% chance of being a modest success and profiting $0.9
Zina [12379]

P(S) = Probability of Smash = 0.05 (5%)
P(M) = Probability of Modest = 0.5 (50%)
P(F) = Probability of Flop = 0.45 (45%)
Based on this, we utilize the model for discrete random variables, leading to:
E(X) = (0.05 * 5.2) + (0.5 * 0.9) + (0.45 * 0)
= 0.26 + 0.45 + 0
= 0.71 Mill'

5 0
2 months ago
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