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romanna
1 month ago
12

If limx→3f(x)=7, which of the following must be true? I. f is continuous at x = 3 II. f is differentiable at x = 3

Mathematics
1 answer:
Zina [12.3K]1 month ago
3 0

Regarding f(x), we cannot ascertain either statement without additional information.

Imagine

f(x)=|x-3|+7=\begin{cases}10-x&\text{for }x3\\0&\text{for }x=3\end{cases}

In this case, (I) is false since, although the limit exists at x\to3 and equals 7, we observe f(3)=0\neq7, which indicates that f(x) is not continuous at that point.

(II) is also valid, as f(x) is not differentiable at x=3; specifically,

\displaystyle\lim_{x\to3^-}f'(x)=\lim_{x\to3}(10-x)'=\lim_{x\to3}(-1)=-1

but

\displaystyle\lim_{x\to3^+}f'(x)=\lim_{x\to3}(x+4)'=\lim_{x\to3}1=1

indicating that the derivative is undefined at x=3.

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(x, y) = (8, 20)

Step-by-step explanation: The equation y = 16 + 0.5x represents a linear relationship that can be illustrated with a graph. This indicates that values for x and y can be located at various points on the line.

The ordered pairs signify that for each x value, there exists a matching y value.

The values listed in a two-column format for x and y all fulfill the equation y = 16 + 0.5x. Observing the first example, the pair (-4, 14) is presented.

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Answer:

Option 2  50 ≤ s ≤ 100

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