A square lot has sides of 39.875 m<br> Which is the best estimate for the perimeter of the lot?

An element with mass 730 grams decays by 28.8% per minute. How much of the element is remaining after 10 minutes, to the nearest

AnnZ [9099]

$\bf \qquad \textit{Amount for Exponential Decay}\\\\
A=P(1 - r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{initial amount}\to &730\\
r=rate\to 28.8\%\to \frac{28.8}{100}\to &0.288\\
t=\textit{elapsed time}\to &10\\
\end{cases}
\\\\\\
A=730(1-0.288)^{10}\implies A=730(0.712)^{10}$

6 0

11 days ago

Read 2 more answers

Decide whether the set A of positive integers divisible by 17 and B the set of positive integers

Inessa [9000]

Answer:

Yes; refer to the question's clarification and the detailed answer below for more information.

Explanation:

Sets are in bijection if there is a bijective function connecting them.

This implies that the question can be interpreted as: can sets A and B be related via a bijective function?

A bijective function must be both injective and surjective, which means it is reversible.

Injective indicates that each element in the domain corresponds uniquely to an element in the codomain.

Surjective denotes that every element in the codomain relates to exactly one element in the domain.

This ensures there are no unmatched elements.

If we consider set A as the function's domain and set B as the codomain.

The core question then becomes: can the set {17, 34, 51, 68, 85,...} be in bijection with the set {11, 22, 33, 44, 55,...}?

Notice that the two sets share no common elements, as 17 and 34 are coprime.

A bijective function can only be established between sets A and B or B and A if both sets possess the same cardinality (number of elements).

Indeed, the cardinality of sets A and B is identical: both sets are of equal size, affirming that a bijective relationship exists between them.

4 0

29 days ago

Ajay spends 6 hours at school. It takes him 35 min to travel from home to school and the same amount of time to return . He retu

tester [8842]

I'm fairly certain the answer is 7:50 am.

4 0

1 month ago

Read 2 more answers

A ship sails at 15 miles per hour, while it can motor at 5 miles per hour. It sails for 6 hours to its destination but has to mo

tester [8842]

Greetings!

The conclusion is:

The return trip will take 18 hours.

Reasoning:

To determine the duration of the return journey, we must calculate the distance from the destination back to the starting point.

The ship travels at 15 miles per hour (mph) over 6 hours, yielding a distance of:

$x=x_o+v*t\\\\x=0+15mph*6hours=90miles$

The distance from the starting point to the destination is 90 miles, and for the return trip, the motor operates at a speed of 5 mph. Thus, computing the time taken gives us:

$Distance=v*t\\\\t=\frac{Distance}{v}=\frac{90miles}{5mph}=18hours$