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Verdich
2 months ago
3

Complete the function definition to output the hours given minutes.

Computers and Technology
2 answers:
8_murik_8 [964]2 months ago
5 0

Answer:

def output_minutes_as_hours(orig_minutes): \\\

  output_minutes_as_hours = orig_minutes / 60 \\\

  print('{}'.format(output_minutes_as_hours)) \\\

minutes = float(input())

output_minutes_as_hours(minutes)

Explanation:

def output_minutes_as_hours(orig_minutes): #Define minutes into hours (input orig_mins) ///

  output_minutes_as_hours = orig_minutes / 60 #Convert minutes to hours by dividing input orig_mins by 60mins ///

  print('{}'.format(output_minutes_as_hours)) # Output formatted string for minutes as hours post conversion \\\

minutes = float(input())

output_minutes_as_hours(minutes)

ivann1987 [1K]2 months ago
3 0

Answer:

def output_minutes_as_hours(orig_minutes):

return orig_minutes / 60

a = output_minutes_as_hours(231)

print(a)

Explanation:

The function defined above serves to convert minutes into hours based on input from minutes. Note: This function is crafted in Python, with the conversion based on the fact that one hour equals 60 MINUTES. Thus, we divide the given time by 60 to find the equivalent in hours.

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Harlamova29_29 [1022]

Answer:

In my opinion, the coding structure's elements assist the software or CPU in interpreting or directing the programming.

Explanation:

6 0
1 month ago
Suppose we are sorting an array of eight integers using quicksort, and we have just finished the first partitioning with the arr
Rzqust [1037]

Answer:

c. The pivot could either be 7 or 9.

Explanation:

When sorting an array of eight integers through quicksort, the first partitioning indicates that either 7 or 9 may serve as the pivot. Observing the array, it is specifically 7 and 9 that occupy their correct positions within the ordered array. All integers preceding 7 and 9 are lesser, and all numbers following them are greater. Therefore, it suggests that the pivot is located between 7 and 9.

6 0
1 month ago
In cell F15, insert a function that will automatically display the word Discontinue if the value in cell D15 is less than 1500,
ivann1987 [1066]

Answer:

=IF(D15<1500, "Discontinue", "No Change")

Explanation:

In an Excel environment, you should navigate to cell F15 and apply the IF function. The structure of the IF function is

IF(<condition>, <value if true>, <value if false>)

Your condition is placed before the first comma, which is D15 < 1500.

The second segment, located before the second comma, is the text to display when D15 is below 1500, which is "Discontinue".

Finally, the last part should show text if D15 is 1500 or higher, which is "No Change".

The complete formula can be expressed as =IF(D15<1500, "Discontinue", "No Change")

3 0
1 month ago
Write a class named Taxicab that has three **private** data members: one that holds the current x-coordinate, one that holds the
amid [951]

Response:

Refer to the explanation

Details:

class Taxicab():

def __init__(self, x, y):

self.x_coordinate = x

self.y_coordinate = y

self.odometer = 0

def get_x_coord(self):

return self.x_coordinate

def get_y_coord(self):

return self.y_coordinate

def get_odometer(self):

return self.odometer

def move_x(self, distance):

self.x_coordinate += distance

# increase the odometer with the absolute distance

self.odometer += abs(distance)

def move_y(self, distance):

self.y_coordinate += distance

# increase odometer with the absolute distance

self.odometer += abs(distance)

cab = Taxicab(5,-8)

cab.move_x(3)

cab.move_y(-4)

cab.move_x(-1)

print(cab.odometer) # will output 8 3+4+1 = 8

7 0
1 month ago
Given positive integer numInsects, write a while loop that prints that number doubled without reaching 200. Follow each number w
zubka84 [1067]

Answer:

The code placed where "/*Your solution goes here */" is as follows:

while(numInsects<200) // while loop

       {

            System.out.print(numInsects+" "); // output statement

            numInsects=numInsects*2; // operation to double the value.

       }

Output:

  • If the input is 16, the result is 16 32 64 128.
  • If the input is 25, the result is 25 50 100.

Explanation:

  • The above Java code fills the section designated as "Your solution" and will operate correctly.
  • The program accepts a user input and continues to print double the value until it reaches 200 or more.
  • The while loop evaluates whether the value remains below 200. If so, the operation proceeds; otherwise, it stops.
5 0
1 month ago
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