This program will calculate the rise in ocean levels over 5, 10, and 50 years, Part of the program has been written for you. The
part that has been written will read in a rise in ocean levels (per year) in millimeters. This value is read into a variable of type double named risingLevel. You will be completing the program as follows Output the value in risingLevel. This should be the first line of output. The output should be as follows (assume risingLevel has a value of 2.1) Level: 2.1 The number of millimeters higher than the current level that the ocean's level will be in 5 years (assuming the ocean is rising at the rate of risingLevel per year). This is your second line of output. The output will be as follows Years: 5, Rise: 10.5 The number of millimeters higher than the current level that the ocean's level will be in 10 years (assuming the ocean is rising at the rate of risingLevel per year). This is your third line of output. The output will be as follows (for a risingLevel" of 2.1 Years: 10, Rise: 21 The number of millimeters higher than the current level that the ocean's level will be in 50 years (assuming the ocean is rising at the rate of risingLevel per year). This is your final line of output.The output will be as follows (for a risingLevel" of 2.1) Years: 50, Rise: 105 For each of the above you need to output the number of years and the total rise in ocean levels for those years. This is all based on the value in risingLevel For example: ArisingLevel of 2.1 for 5 years would have the following output: Level: 2.1 Years: 5, Rise: 10.5 Years: Years: 50, Rise: 105 10, Rise: 21 Your output must have the same syntax and spacing as above
1 answer:
Answer:
Here is the C++ code:
#include <iostream> //for utilizing input and output functions
using namespace std; //for defining objects cin cout
int main(){ //beginning of the main function
double risingLevel; //declares a variable of type double to store the rising level
cin>>risingLevel; //captures the risingLevel input from the user
cout<<"Level: "<<risingLevel<<endl; //outputs the rising level
cout << "Years: 5, Rise: " << risingLevel * 5<<endl; //outputs the increase in ocean level over 5 years
cout << "Years: 10, Rise: " << risingLevel * 10<<endl; //outputs the increase in ocean level over 10 years
cout << "Years: 50, Rise: " << risingLevel * 50<<endl; //outputs the increase in ocean level over 50 years
}
Explanation:
The functioning of the program is as follows:
Supposing the user inputs a rising level of 2.1, then,
risingLevel = 2.1
At that point, the first print statement (cout):
cout<<"Level: "<<risingLevel<<endl; outputs the value of risingLevel to the display. Therefore, this line shows:
Level: 2.1
Next, the program proceeds to the following statement:
cout << "Years: 5, Rise: " << risingLevel * 5<<endl;
which calculates the increase in ocean levels for a duration of 5 years using the equation:
risingLevel * 5 = 2.1 * 5 = 10.5
It subsequently shows the calculated result on the display. So, this line shows:
Years: 5, Rise: 10.5 Then, the control shifts to the next statement:
cout << "Years: 10, Rise: " << risingLevel * 10<<endl;
that computes the rise in ocean levels over a span of 10 years using the equation:
risingLevel * 10 = 2.1 * 10 = 21
It then showcases the calculated figure on the output screen. Thus, the output is:
Years: 10, Rise: 21
Next, the program control progresses to this statement:
cout << "Years: 50, Rise: " << risingLevel * 50<<endl;
which determines the rise in ocean levels for a duration of 50 years using the equation:
risingLevel * 50 = 2.1 * 50 = 105
This then displays the computed result on the output screen, leading to the output:
Years: 50, Rise: 105 Consequently, the complete output from the program will be:
Level: 2.1 Years: 5, Rise: 10.5
Years: 10, Rise: 21Years: 50, Rise: 105
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Answer:
public void printAll(){ // member function petAll()
super.printAll(); // invokes printAll() method from the superclass (base class) AnimalData using the super keyword
System.out.print(", ID: " + idNum);} // displays the ID saved in the idNum field of the PetData class
Explanation:
This is the full PetData class:
public class PetData extends AnimalData { //
private int idNum;
public void setID(int petID) {
idNum = petID; }
// FIXME: Implement printAll() member method
/* Your solution goes here */
public void printAll(){
super.printAll();
System.out.print(", ID: " + idNum);} }
The PetData class is a subclass that inherits from the base class AnimalData.
This class contains a private field, idNum, which is designated for storing the ID value.
It includes a method setID which takes petID as a parameter that corresponds to idNum. Essentially, this acts as a mutator to set the user ID.
Additionally, there is a printAll() method that makes use of the super keyword to call the printAll() method from the base class, AnimalData.
Using super refers to objects of the base class.
Here, the super keyword is utilized with the method name from the subclass PetData to avoid confusion, as both AnimalData and PetData have a method named printAll().
During the main() method, users will enter values for userName, UserAge, and UserID. For example, if the user inputs Fluffy as the name, 5 as the age, and 4444 as the userID. Then, calling userPet.printAll(); will execute the printAll() method from the PetData class since userPet is an instance of PetData.
When this method executes, it will call the printAll() of AnimalData class which outputs the Name and Age, while printAll() of PetData prints the ID. Consequently, the resulting output will be:
Name: Fluffy, Age: 5, ID: 4444
