Ask question

Ask question

All categories

21 day ago

7

Kayla has a bowl of beads that contains 42 yellow beads, 28 green beads, 12 white beads, and 18 red beads. She randomly draws a

bead from the bowl.
The probability of Kayla not drawing a yellow or a green bead is
%. The probability of Kayla drawing a red or a green bead is
%

1 answer:

AnnZ [9K]21 day ago

5 0

Count the total colors of beads

42+28+12+18=100

Next, calculate the sum of the yellow and green beads

42+28=70

To determine the count of beads that are neither yellow nor green, subtract from the total

100-70=30

The first answer thus is 30/100 -> 3/10 -> 30%

Now, tally the red and green beads

28+18=46

Thus, the next answer is

46/100 -> 23/50 -> 46%

You might be interested in

If xy + 5ey = 5e, find the value of y'' at the point where x = 0.

Zina [9157]

Response:

1 (only applicable if e is not zero)

Detailed explanation:

xy + 5ey = 5e

0y + 5ey = 5e

y = 5e/5e

y = 1

6 0

26 days ago

Samuel rotated PLUTO 90° clockwise about the origin to generate P'L'U'T'O'.

tester [8808]

Response:.

Detailed explanation:

5 0

10 days ago

Use the geometric definition of the cross product and the properties of the cross product to make the following calculations. (a

tester [8808]

Answer:

Step-by-step explanation:

We understand that

$\vec{i}\times \vec{j}=\vec{k}$

$\vec{j}\times \vec{k}=\vec{i}$

$\vec{k}\times \vec{i}=\vec{j}$

(a) $\left [ \left ( \hat{i}+\hat{j}\right )\times \hat{i}\right ]\times \hat{j}$

$=\left [ \hat{i}\times \hat{i}+\hat{j}\times \hat{i}\right ]\times \hat{j}$

$=\left [ 0-\hat{k}\right ]\times \hat{j}$

$=\hat{i}$

(b) $\left ( \hat{j}+\hat{k}\right )\times \left ( \hat{j}\times \hat{k}\right )$

$=\left ( \hat{j}+\hat{k}\right )\times \left ( \hat{i}\right )$

$=\hat{k}+\hat{j}$

(c) $4\hat{i}\times \left ( \hat{i}+\hat{j}\right )$

$=4\hat{i}\times \hat{i}+4\hat{i}\times \hat{j}$

$=0+4\hat{k}$

(d) $\left ( \hat{k}+\hat{j}\right )\times \left ( \hat{k}-\hat{j}\right )$

$=\hat{k}\times \hat{k}-\hat{k}\times \hat{j}+\hat{j}\times \hat{k}-\hat{j}\times \hat{j}$

$=0+\hat{i}+\hat{i}-0$

$=2\hat{i}$

6 0

1 month ago

Consider the equation pV=kTN , where k is a constant. Select all of the correct answers that describe the variation between vari

PIT_PIT [9101]

Answer:

Refer to the following:

Step-by-step explanation:

Rule: If variables appear on the same side of the equation, they have INVERSE variation.

If the variables are located on opposite sides of the equation, they have DIRECT variation.

a) T and V

Opposite sides
Directly related

b) p and T

Opposite sides
Directly related

c) N and V

Opposite sides
Directly related

d) N and T

Same side
Inversely related

e) p and N

Opposite sides
Directly related

f) V and P

Same side
Inversely related.

4 0

23 days ago

Colin invests £2350 into a savings account. The bank gives 4.2% compound interest for the first 4 years and 4.9% thereafter. How

zzz [9066]

To tackle this, we will apply the compound interest formula: $A=P(1+ \frac{r}{n} )^{nt}$
where
$A$ represents the final amount after $t$ years
$P$ denotes the initial investment
$r$ is the interest rate expressed as a decimal
$n$ indicates the frequency of interest compounding annually

Initially, for the first four years, we have: $P=2350$ , $r= \frac{4.2}{100} =0.042$ , $t=4$ , and as the problem does not specify the frequency of compounding, we will assume it occurs annually; thus, $n=1$ . Now, let's insert these values into our formula:
$A=P(1+ \frac{r}{n} )^{nt}$
$A=2350(1+ \frac{0.042}{1} )^{(1)(4)}$
$A=2350(1+0.042)^{4}$
$A=2770.38$

For the subsequent six years, the initial amount will be the resulting figure from our prior calculation, which means $P=2770.38$ . We also know that: $r= \frac{4.9}{100} =0.049$ , $t=6$ , and $n=1$ . Let's substitute these figures back into our formula:
$A=P(1+ \frac{r}{n} )^{nt}$
$A=2770.38(1+ \frac{0.049}{1})^{(1)(6)$
$A=2770.38(1+0.049)^6$
$A=3691.41$

In conclusion, Collin's account will contain <span>£3691.41 after a decade.</span>

4 0

1 month ago