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Julli
1 month ago
7

if a student scored 78 points on a test where the mean score was 84.5 and the standard deviation was 3.1. the student's z score

is
Mathematics
1 answer:
Inessa [12.5K]1 month ago
5 0

Answer:

(value - mean)/standard deviation.

Now substitute 78 for the value, 84.5 for the mean, and 3.1 for the standard deviation.

Step-by-step explanation:

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What are the eight-digit grid coordinates for benchmark 86 (circled in red)?
lawyer [12517]

Answer:

An eight-digit grid coordinate allows for precision within 10 meters.

Step-by-step explanation:

Grid coordinates are designed to direct accurately to a specific location by using a map that includes equally spaced vertical and horizontal lines, each assigned numbers to outline a place. The intersection of these vertical and horizontal lines has unique identifiers and creates small sections called grid squares.

The precision increases with the number of digits in the coordinate; an eight-digit designation gives accuracy to the nearest 10 meters.

3 0
1 month ago
What is the logarithm of the equilibrium constant, log K, at 25°C of the voltaic cell constructed from the following two half-re
lawyer [12517]

Answer:

4.0921 reflects the logarithm of the equilibrium constant.

Step-by-step explanation:

Fe^{2+} (aq) +2e^{-}\rightarrow Fe(s); ​E​° = - 0.41 V

Ag^+(aq) + e^-\rightarrow Ag(s); E° = 0.80 V

Iron has a negative reduction potential, indicating its tendency to lose electrons and undergo oxidation, and thus it will be at the anode.

E^{o}_{cell}=Reduction potential of cathode - Reduction potential of anode

E^{o}_{cell}=E^{o}_c-E^{o}_a

=0.80 V-(-0.41 V)=1.21 V

Fe^{2+} (aq) + 2e^{-}\rightarrow Fe(s); ​E​° = - 0.41 V

2Ag^+(aq) + 2e^-\rightarrow 2Ag(s); E° = 0.80 V

Net reaction: Fe(s)+2Ag^{+}\rightarrow Fe^{2+}+2Ag(s)

n = 2

To determine the equilibrium constant, we utilize the correlation with Gibbs free energy, as follows:

\Delta G^o=-nfE^o_{cell}

and,

\Delta G^o=-RT\ln K_{eq}

Aligning these two equations yields:

nfE^o_{cell}=RT\ln K_{eq}

where,

n = electrons transferred = 2

F = Faraday's constant = 96500 C

E^o_{cell} = standard electrode potential of the cell = 1.21 V

R = gas constant = 8.314 J/K.mol

T = reaction temperature = 25^oC=[273+25]=298K

Substituting values into the equation, we arrive at:

2\times 96500\times 1.21 V=8.314\times 298\times \ln K_{eq}

\ln K_{eq}=9.3478

\log K_{eq}=\frac{9.3478}{2.303}=4.0921

4.0921 represents the logarithm of the equilibrium constant.

7 0
1 month ago
At work, Brett must check and record the internal temperature of the freezer on an hourly basis. When working properly, the temp
AnnZ [12381]
The choice is the first one (positive)
3 0
1 month ago
Read 2 more answers
Two parallel lines are crossed by a transversal. Parallel lines x and y are cut by transversal w. On line x where it intersects
AnnZ [12381]

Answer:

118.2°

Step-by-step explanation:

Dos líneas paralelas x e y son cortadas por la transversal w (ver el diagrama adjunto).

Se forman 8 ángulos (denominados 1, 2, 3, 4, 5, 6, 7 y 8).

Los ángulos 1 y 6 son ángulos del mismo lado cuando dos líneas paralelas x e y son cortadas por la transversal w.

Dos ángulos del mismo lado son suplementarios (suman 180°). Esto significa

m\angle 1+m\angle 6=180^{\circ}

Dado m\angle 1=61.8^{\circ}, por lo que

m\angle 6=180^{\circ}-61.8^{\circ}=118.2^{\circ}

8 0
1 month ago
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A jewelry artist is selling necklaces at an art fair. It costs $135 to rent a booth at the fair. The cost of materials for each
lawyer [12517]

Answer:

The artist begins to profit when n > 8.18

That means the quantity of necklaces must exceed 8.18.

Step-by-step explanation:

Given

let n represent the number of necklaces

booth fee= $135

The expense for materials per necklace = $4.5n

the overall selling price for all necklaces = $12n

total costs= booth fee + material costs = $135 + 4.5n

profit = selling price - total costs

12n > 135 + 4.50n

By solving for n, we find

12n=135 + 4.50n

12n + 4.5n = 135

16.5n = 135

n = 135/16.5

n = 8.18

Hence, the artist achieves profits when n > 8.18.

8 0
1 month ago
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