Answer:
The distances on Alysson's map representing the routes from Mumbai to Bangalore and Delhi should maintain the same proportion as this ratio:

Step-by-step explanation:
The inquiry pertains to scale and ratios
Organizing the details:
Mumbai:
to Bangalore
Mumbai is
km away from Delhi
Given that the distances among the cities are proportional, we need to establish the ratio of the distance from Mumbai to Bangalore against the distance from Mumbai to Delhi.

Two-fifths (

) of the square of the variable j (j²)
j²
Answer: The coordinates of point T are (13, -6).
Step-by-step explanation: Given that point S is the midpoint of segment RT, with coordinates R(-9, 4) and S(2, -1),
we need to determine the coordinates of point T.
The midpoint formula states that the midpoint between points (a, b) and (c, d) is ((a + c)/2, (b + d)/2).
Let T be (h, k). According to the problem:


Solving these equations yields T at (13, -6).
So, the required coordinates for point T are (13, -6).
Each minute, you need to multiply the mass by 27.7% or 0.277
after 1 minute, it's one multiplication
after 2 minutes, it’s two multiplications
3, three times
and so forth
consequently, after 13 minutes, you'd multiply 13 times or 0.277^13
thus what is 970g * 0.277^13 =?
Hello! You need to calculate a 99% confidence interval for the difference in mean lifespan between two tire brands. Each tested car was assigned one tire from each brand randomly on the rear wheels, allowing for paired sample analysis.
Brand 1 Brand 2 X₁-X₂
car 1: 36,925; 34,318; 2.607
car 2: 45,300; 42,280; 3.020
car 3: 36,240; 35,500; 0.740
car 4: 32,100; 31,950; 0.150
car 5: 37,210; 38,015; -0.0805
car 6: 48,360; 47,800; 1.160
car 7: 38,200; 37,810; 0.390
car 8: 33,500; 33,215; 0.285
n= 8
The study variable is defined as Xd= X₁-X₂, where X₁ represents the tire lifespan (in km) from Brand 1 and X₂ represents Brand 2. Thus, Xd is the difference in tire lifespan.
Xd~N(μd;δd²) (normality test p-value is 0.4640).
For calculating the confidence interval, the best statistic is the Student's t using the following formula:
t= (xd[bar] - μd)/(Sd/√n) ~t₍ₙ₋₁₎
sample mean: xd[bar]= 0.94
standard deviation: Sd= 1.29
= 3.355
xd[bar] ±

*(Sd/√n) ⇒ 0.94 ± 3.355*(1.29/√8)
[-0.65;2.54]km.
The CI can be compared to bilateral hypothesis testing:
H₀:μd=0
H₁:μd≠0
using significance level of 0.01.
Since the confidence interval includes zero, we do not reject the null hypothesis, indicating no significant difference between the tire brands.
Hope you have a fantastic day!