answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
koban
2 months ago
14

In 2011, the world's largest pumpkin weighed 825 kilograms. An average-sized pumpkin weighs 5,000 grams. The 2011 world-record p

umpkin weighs _____ kilograms more than an average-sized pumpkin.
Mathematics
1 answer:
Leona [12.6K]2 months ago
6 0
1000 g = 1 kg
5,000 g = 5 kg
825 kg - 5 kg = 820 kg

<span>The pumpkin that set the world record in 2011 weighs __820 kg___ more than an average pumpkin.</span>
You might be interested in
J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
babunello [11817]

The 99% confidence interval for the actual mean difference between average mail-order and internet purchase amounts falls within [$(-31.82), $12.02].

Step-by-step clarification:

We know a random sample of 16 mail-order sales receipts shows a mean sale amount of $74.50 and a standard deviation of $17.25.

For internet sales, a random sample of 9 receipts gives a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal value utilized for constructing a 99% confidence interval for the true mean difference is given by;

                      P.Q.  =  

 ~

where,

= sample mean of mail-order sales = $74.50 \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }t__n_1_+_n_2_-_2

= sample mean of internet sales = $84.40

\bar X_1 = standard deviation for mail-order sales = $17.25

\bar X_2 = standard deviation for internet sales = $21.25

s_1 = number of mail-order sales receipts = 16

= number of internet sales receipts = 9s_2

Furthermore,  

 =  n_1 = 18.74

n_2

The actual mean difference between average mail-order and internet purchases is denoted by (s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }\sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} }

).

Thus, the 99% confidence interval for (\mu_1-\mu_2) is expressed as;

      = \mu_1-\mu_2 Here, the t critical value at the 0.5% significance level with 23 degrees of freedom is 2.807.           =

          = [$-31.82, $12.02](\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_) \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Therefore, the 99% confidence interval for the true mean difference between average mail-order and internet purchases is [$(-31.82), $12.02].

(74.50-84.40) \pm (2.807 \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

5 0
2 months ago
What teacher exhibited the most consistent performance over this 5 year span
lawyer [12517]
Is there meant to be an image?
4 0
3 months ago
John averages 58 words per minute on a typing test with a standard deviation of 11 words per minute. Suppose John's words per mi
Zina [12379]

Answer:

When x = 72, the z score is:

z = \frac{72-58}{11}= 1.273

The average is 58

This z-score indicates that x= 72 is 1.273 standard deviations above the mean.

Step-by-step explanation:

Let’s consider the following details for this question: John's typing speed on a test is assumed to follow a normal distribution. Let X denote the number of words he can type in a minute. Hence, X ~ N(58, 11). It’s important to round the result to three decimal points if needed.

Provide your response below for words per minute on a typing test conducted on Sunday. The z score when x = 72 is

In this scenario, we acknowledge that the variable under consideration is represented by a normal distribution:

X \sim N (\mu= 58, \sigma=11)

The formula for the z score is as follows:

z = \frac{X -\mu}{\sigma}

By substituting values, we derive:

z = \frac{72-58}{11}= 1.273

The mean is 58

This z-score indicates that x= 72 is 1.273 standard deviations higher than the mean.

8 0
2 months ago
The lengths of the sides of triangle PQR are consecutive even integers. The perimeter of triangle PQR is 42 cm. What is the leng
PIT_PIT [12445]
Let the three consecutive even integers representing the sides of triangle PQR be defined as x, (x + 2), and (x + 4). Given that the perimeter of triangle PQR equals 42 cm.
6 0
1 month ago
Write a difference quotient that best approximates the instantaneous rate of change of g at x=0
lawyer [12517]

Step-by-step explanation:

The difference quotient represents the slope of the line connecting two points on a curve. To achieve the most accurate estimate, we need to use points that are nearest to x = 0. For this problem, the relevant points are (-0.001, 1.999) and (0.001, 2.001).

m = (2.001 − 1.999) / (0.001 − (-0.001))

m = 1

7 0
2 months ago
Other questions:
  • Fill in the blank. Given O below, you can conclude that OD is congruent to ___________.
    5·2 answers
  • Angel, Juan y Ricardo son hermanos. Durante el mes de agosto viajaron a visitar a sus padres que viven en Huancayo. Angel llega
    5·1 answer
  • Trapezoid $RSTU$ is a cross section of a lampshade. The diagonals of $RSTU$ are congruent, and the measure of $\angle S$ is $112
    13·1 answer
  • This sequence represents the diameters of circles used to create an art project:2.5 cm, 3.1 cm, 3.7 cm, 4.3 cmLet f(n) represent
    15·1 answer
  • A survey of 132 students is selected randomly on a large university campus. They are asked if they use a laptop in class to take
    12·1 answer
  • Anna is no more than 3 years older than 2 times Jamie’s age. Jamie is at least 14 and Anna is at most 35. Which system of linear
    13·2 answers
  • Suppose that a high school marching band has 125 members. Of these 125 band members, 41 are seniors, 24 play the trumpet, and 10
    5·1 answer
  • 4. An airplane is traveling at a speed of 724 km/hr at a direction of 30 degrees. The wind is blowing from the west at 32 km/hr.
    7·1 answer
  • Chester, the dog, loves to eat treats. He has eaten twice as many today as yesterday. He has eaten a total of 15 dog treats in b
    15·1 answer
  • Which pairs of rectangles are similar polygons?<br><br> Select each correct answer.
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!