Response:
1 B
2 A
3 B
Detailed explanation:
1
The population refers to the entire sample from which part of the event is being analyzed. Essentially, in a set, the population includes everything collectively. From the provided statement, our goal is to identify the population. The population is B.
All NBA players since 1966. This selection is because it is from this set that the draft picks were chosen, ultimately narrowed down to 45% being center backs.
2
The specified attribute is A.
Being a No. 1 draft pick, as it's the central focus of the statement itself
3
B sample proportion. As mentioned earlier, the population consists of all NBA players since 1966, so a population proportion would contain a statement like this.
45% of all NBA players since 1966...
Consequently, it's a sample proportion since it pertains to the draft pick, as opposed to the NBA players
The response is $12.50. This might not be correct, but it's worth testing.
Sample Answer: No, Ingrid's statement is incorrect. In this situation, the starting point is at 170 feet, which denotes the y-intercept. The reduction of 4 feet per year symbolizes the rate of change, or slope. In the slope-intercept equation format, y = mx + b, with 'm' denoting the slope and 'b' signifying the y-intercept, the accurate equation would be y = −4x + 170.
To address this issue, the procedure below should be utilized:
1- The Law of sines can be applied as follows:
The unknown angle can be determined by: 180°-65°-45°=70°
- The <span>distance Jake travels to the store is:
30/Sin(70°)=x/Sin(45°)
x=22.57
- The distance Maddie travels to the store is:
</span>30/Sin(70°)=y/Sin(65°)
<span> y=28.93
- The difference calculated is: 6.36
Thus, the result shows that the difference is 6.36 m.</span>
Let’s define x as the amount invested by Sam in the first year.
Here are the corresponding expressions derived from the provided descriptions for Sam's investments.
For Sam:
2nd year: investment = 5x/2 - 2000
3rd year: investment = x/5 + 1000
The total Sam invested is:
x + (5x/2 - 2000) + (x/5 + 1000)
Next, we can form the expressions for Sally’s investments.
For Sally
1st year: investment = 3x/2 - 1000
2nd year: investment = 2x - 1500
3rd year: investment = x/4 + 1400
Thus, Sally's total investment is,
total = (3x/2 - 1000) + (2x - 1500) + (x/4 + 1400)
Setting both totals equal gives us:
(x) + (5x/2 - 2000) + (x/5 + 1000) = (3x/2 - 1000) + (2x - 1500) + (x/4 + 1400)
Solving for x,
x = 2000
For Sally's investment for the third year:
investment = x/4 + 1400 = (2000/4 + 1400) = 1900
RESULTS:
Sam's first year = $2000
Sally's third year = $1900
