A(n)=a(1)+(n-1)d=
a(n)=2+(n-1)2=2+2n-2=2n
Let the events be defined as follows:
A=Nathan suffers from an allergy
~A=Nathan does not suffer from an allergy
T=Nathan receives a positive test result
~T=Nathan does not receive a positive test result
According to the provided data,
P(A)=0.75 [ probability indicating that Nathan is allergic ]
P(T|A)=0.98 [ probability of obtaining a positive test result if Nathan is allergic to Penicillin]
We aim to calculate the probability that Nathan is both allergic and tests positive
P(T n A)
Using the definition of conditional probability,
P(T|A)=P(T n A)/P(A)
By substituting the known values,
0.98 = P(T n A) / 0.75
We then solve for P(T n A)
P(T n A) = 0.75*0.98 = 0.735
Hope this assists you!!