Answer:
AUGUCCCACGAUGGGUGA
Methionine- Serine- Histidine- Aspartate- Glycine- Stop
Explanation:
During the process of gene expression, DNA, which contains genetic information, is transcribed into mRNA, and this mRNA is then translated into a sequence of amino acids. This transcription abides by the rules of complementary base pairing, translating as A-U, G-C, and T-A.
In mRNA, nucleotide sequences are organized into sets of three bases known as CODONS. Each of these codons corresponds to a specific amino acid.
In this scenario, a piece of DNA encodes methionine, serine, histidine, aspartate, and glycine after translation. However, a mutation leads to the sequencing shown: 3' – TACAGGGTGCTACCCACT – 5'.
The mutated DNA's corresponding mRNA sequence would be: AUGUCCCACGAUGGGUGA
Throughout translation, these codons yield the following amino acids:
AUG - methionine
UCC - Serine
CAC - Histidine
GAU - Aspartate
GGG - Glycine
UGA - Stop codon
Therefore, the resultant peptide chain from the revised DNA sequence will be: Methionine- Serine- Histidine- Aspartate- Glycine- Stop
