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Anettt
4 days ago
10

Based on prior experiments, you have determined that for a culture of S. aureus an absorbance reading of 1.0 AU650 is approximat

ely equal to 5.75 x 106 cells/mL. How many cells should be present after 8 generations in a 1 mL culture, if the initial cell culture had an absorbance reading of 1.25
Biology
1 answer:
enyata [2.5K]4 days ago
7 0

Answer:

18.38 × 10⁸.

Explanation:

Cell absorbance is directly proportional to their density

A\alpha cells/mL

A=K ×cells/mL ( Here, K is a constant)

Thus, A/ (cells/mL)=K

Hence, A1/( cells/mL)1=A2/ ( cells/mL)2

Where A1 represents initial absorbance, (cells/mL)1= initial concentration, (cells/mL)2= final concentration, A2= final absorption

Therefore, ( cells/mL)2=(A2* (cells/mL)1 ) / A1

= (1.25 × 5.75 ×10⁶)/1

= 7.18 ×10⁶.

Consequently, the final bacterial concentration in the culture with an absorbance of 1.25 =  7.18 ×10⁶.

Thus, after 8 generations

The growth of cells is geometric, meaning the cell count doubles with each generation, resulting in quadrupling the initial amount after the second generation.

The nth term of geometric progression is expressed as arⁿ⁻¹

where a is the first term, r =2 ( r=nth term/ (n-1) th term)

where n=9 ( n= number of generations+1)

The 9th term therefore becomes (7.18 ×10⁶ × 2⁸)

= 18.38 × 10⁸.

As a result, the number of cells in 1 mL after 8 generations is 18.38 × 10⁸.

Thus, the solution is 18.38 × 10⁸.

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