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OleMash
20 days ago
12

If p(x) = 5(x^2+1)+16 what is the value of p(11)

Mathematics
2 answers:
lawyer [9.2K]20 days ago
7 0

Answer:

p(11) = 626.

Step-by-step explanation:

We start with the equation: p(x) = 5(x²+1)+16.

We need to find p(11).

Plugging in x = 11 gives:

p(11) = 5((11)²+1)+16.

p(11) = 5(121 + 1) + 16.

p(11) = 5(122) + 16.

p(11) = 610 + 16.

p(11) = 626.

Consequently, p(11) equates to 626.

zzz [9K]20 days ago
4 0
5(11 squared + 1) plus 16

5(121 + 1) plus 16

5(122) plus 16

605 plus 16

p(11) equals 626
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