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beks73
5 days ago
5

Addison wants to cut 21 centimeters of lace, but her ruler is only calibrated in millimeters. How many millimeters of lace shoul

d she cut?
Mathematics
1 answer:
Zina [12.1K]5 days ago
5 0
1 cm is equivalent to 10 mm

Thus, (21 cm)(10) equals 210 mm
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The measure of central angle QRS is StartFraction 8 pi Over 9 EndFraction radians. What is the area of the shaded sector? 36Pi u
babunello [11473]

The illustration is omitted. Please see the attachment below.

Answer:

The area of the shaded sector is 144π square units.

Step-by-step breakdown:

Given:

The central angle for the sector is, \theta=\frac{8\pi}{9}\ rad

The circle's radius is, R=18\ units

The area of a sector with radius 'R' and angle \theta can be determined with:

A=\frac{1}{2}R^2\theta

Substituting \theta=\frac{8\pi}{9},R=18 gives

A=\frac{1}{2}\times (18)^2\times \frac{8\pi}{9}\\\\A=(\frac{324\times 4}{9})\pi\\\\A=(36\times 4)\pi\\\\A=144\pi\ units^2

Thus, the area of the shaded sector calculates to 144π square units.

5 0
1 month ago
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Lines m and n are cut by transversal l. Lines m and n are cut by transversal l. On line m where it intersects line l, 4 angles a
babunello [11473]

∠1 and ∠8 are alternate exterior angles while ∠3 and ∠6 are alternate interior angles.

step-by-step explanation:

When transversal l intersects lines m and n, the angles formed outside each line on the opposite side of the transversal constitute alternate angles (like ∠1 and ∠8). In contrast, alternate interior angles appear on opposite sides but are located between the two lines (like ∠3 and ∠6).

Learn More

Keywords: Transversal, angles

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1 month ago
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Metal Melting Point (°C) Boiling Point (°C) Density in Solid State (g/cm3) Copper 1,083 2,567 8.3–9.0 Lead 327.3 1,750 11.3 Gold
lawyer [12277]
Based on the provided information about the metals' melting point, boiling point, and density, the response is A. The gold sample transitions from liquid to gas at the highest temperature, while the copper sample occupies the most volume. Gold's boiling point is the highest at 2660, and copper has the lowest density, which correlates with a larger volume since density is defined as mass divided by volume. 
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10 days ago
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Three ships, A, B, and C, are anchored in the atlantic ocean. The distance from A to B is 36.318 miles, from B to C is 37.674 mi
Leona [12278]

Let's sketch the triangle.

The sides are a= 37.674 miles

b= 11.164 miles

c= 36.318 miles

We'll apply the cosine rule for angle calculations

(since the sine law cannot be employed without knowing any angle measurements).

The cosine law is given by

c^{2} = a^{2} +b^{2} -2ab cos C

Substituting the values results in

(36.318)^{2} = (37.674)^{2} + (11.164)^{2} - 2(37.674)(11.164). Cos C

1318.997 = 1419.33 + 124.634 - 841.184. Cos C

1318.997 = 1543.964 - 841.184. Cos C

841.184. Cos C = 1543.964-1318.997

841.184. Cos C = 224.967

Cos C = \frac{224.967}{841.184}

cos C = 0.267

C = 74.48°

We can find angle A using the sine law

\frac{a}{SinA} = \frac{c}{Sin C}

\frac{37.674}{Sin A} = \frac{36.318}{Sin 74.48}

Sin A = \frac{37.674. sin 74.48}{36.318}

Sin A = \frac{37.674 X 0.963}{36.318}

Sin A = 0.998

A= sin^{-1} (0.998)

A = 87.38°

The third angle B can be determined by calculating 180° minus the sum of angles A and C

B = 180-(74.48 + 87.38)

B = 180 - 161.86

B = 18.14°

Thus, we have calculated all three angles (as shown in the attached figure).

7 0
1 month ago
Joseph and Isabelle left Omyra’s house at the same time. Joseph jogged north at 8 kilometers per hour, while Isabelle rode her b
Leona [12278]
The formula for distance in this scenario is:
d ^ 2 = (12 * 1.5) ^ 2 + (8 * 1.5) ^ 2
Rewriting gives us:
d ^ 2 = (18) ^ 2 + (12) ^ 2
d ^ 2 = 324 + 144
d ^ 2 = 468
d = √(468)
d = 21.63 Km
Answer:
1) She failed to calculate the total distance each had covered in 1.5 hours.
2) She should have applied 12 km for Joseph's distance and 18 km for Isabelle's distance.
8 0
17 days ago
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