Choose all the weights that are equal to 1 ton 200 pounds.

Answer:

10

Step-by-step explanation:

If there’s a direct correlation between variables x and y, it can be expressed as

y = kx,

where y is the dependent variable

x is the independent variable

k signifies the constant of variation

_____________________________

For the first scenario

y = 400

x = r

using y = kx, we can derive the relation:

400 = kr

To find k here:

k = 400/r

For the second scenario

y = r

x = 4

again using y = kx, the relationship is given by:

r = 4k

Solving for k:

k = r/4

Since both conditions provide the same equation, k will have the same value in both cases.

Thus, we conclude:

400/r = r/4

=> 400*4 = r*r

=> 1600 = r^2

Hence, r is calculated to be 40.

Thus, k = r/4 = 40/4 = 10.

The constant of variation is confirmed to be 10, which is the correct answer.

Verification:

k = 400/r = 400/40 = 10

Response:

A 120 cm long pipe produces resonance at wavelengths of 480 cm, 160 cm, and 96 cm, but fails to resonate with any wavelengths longer than those. Consequently, this pipe is classified as:

A. closed at both ends

B. open at one end and closed on the other

C. open at both ends.

D. we cannot determine since we lack information about the sound frequency.

The correct answer is:

B. open at one end and closed at the other.

Explanation in steps:

The given data states that the pipe has a length of

= 120 cm

with wavelengths = 480 cm

                             

= 160 cm and = 96 cm

We need to ascertain if the pipe is open, closed, or of an open-closed nature.

Note:

For a pipe open at both ends, the fundamental wavelength is 2L.

For a pipe closed at one end and open at the other, the fundamental wavelength is 4L.

• From this information,
• It appears that this pipe is open at one end and closed at the other.

Now let’s verify with the subsequent wavelengths.

In the case of a pipe with one open end and one closed end:[

Odd multiples of one-quarter wavelength must fit within the length L.

⇒  

                           ⇒  

⇒

                               ⇒  

⇒                                    ⇒  ⇒

                             ⇒  

 Thus, it confirms that the pipe is open at one end and closed at the other.

Every confidence interval correlates with a specific z value. As the confidence interval expands, so does the corresponding z value.
You can compute the confidence interval using the formula:

Here represents the mean, z is the respective z value, s denotes the standard deviation, and n indicates the sample size.
Standard deviation is simply the square root of variance:

For a confidence interval of 95%, the z value is <span>1.960.
</span>Now, we can compute the confidence interval for our income:

Answer:

The total is $4400.

Step-by-step explanation:

A certain company has $90,000 in accounts receivable that are outstanding.

It is estimated that 4% of these receivables will not be collectible.

This 4% translates to: dollars

The current balance in the allowance for doubtful accounts stands at an $800 credit.

Consequently, the final calculation amounts to = dollars

The journal entry to adjust the allowance account requires a debit to Bad Debts Expense for: $4400.

<span>Dada una media de 40k y una desviación estándar de 5k, necesitamos calcular P(x>=30k). Entonces, P((30k-40k)/5k) = P(z<-2) = 1-0.0228 lo que resulta en un 0.9772. Esto indica que hay un 97.72% de probabilidades de que el salario inicial sea de al menos 30k.</span>