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snow_tiger
3 months ago
6

Jessica wants to calculate her grade in her accounting class.she has four test grades (82, 65, 71, and 77) and a homework grade

(92). her highest test grade counts for 25% of her grade, her lowest test grade counts for 15% of her grade, the two remaining tests count for 20% each and her homework grade counts for 20%. what is jessica's weighted average in the class rounded to the nearest whole number
Mathematics
1 answer:
Leona [12.6K]3 months ago
3 0

To determine the solution, calculate the percentage contribution of each test by multiplying the score by its respective percentage and then summing them:


82 *.25 (highest test score) + 65*.15 (lowest test score) + 71*.20 (other tests) + 77*.20 (other tests) + 92*.20 (homework grade)


= 20.5 + 9.75 + 14.2 + 15.4 + 18.4 = 78.25, which is approximately 78% as a whole number

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On a website selling books, three paperback books and five hardcover books cost $80.10, and seven paperback books and four hardc
Zina [12379]
To solve this problem, you'll want to substitute the first equation into the second or the other way around. The equations given are: 1. 3 paperback books + 5 hardcover books = $80.10; 2. 7 paperback books + 4 hardcover books = $100.65. It is helpful to rearrange the first equation to find 5 hardcover books = $80.10 - 3 paperback books, leading to hardcover book = $16.02 - 0.6 paperback books. Now, substitute this into the second equation: 7 paperback books + 4 ($16.02 - 0.6 paperback books) = $100.65, which simplifies to 7 paperback books + $64.08 - 2.4 paperback books = $100.65. This results in 4.6 paperback books = $100.65 - $64.08 = $36.57, thus paperback book = $7.95. You can then use this price in the first equation to determine the hardcover book price: 3 paperback books + 5 hardcover books = $80.10, substituting gives 3($7.95) + 5 hardcover books = $80.10, which leads to 5 hardcover books = $80.10 - $23.85 = $56.25, therefore hardcover book = $11.25. Hence, the total cost for one paperback and one hardcover book is $7.95 + $11.25 = $19.20. 
3 0
2 months ago
The yearly income for an individual with an associate’s degree in 2001 was $53,166 and in 2003 it was $56,970. What is the ratio
Zina [12379]

Response:

8861: 9495

Detailed explanation:

The income ratio for the years 2001 to 2003:

53,166: 56,970

To simplify, divide both sides by 6:

8,861: 9,495

This can't be simplified further, so that is the final result!

8861: 9495

I hope this helps! Have a great day:)

6 0
2 months ago
Read 2 more answers
Points X(6, 8), Y(3, 3), and Z(13, –3) form a triangle. What is the area of △XYZ?
AnnZ [12381]

Answer:

23(6,8)(3,3)(13-3)(-3-)

Step-by-step explanation:

3-6=8-3

+13-3=

23

5 0
3 months ago
Maia had 2064 more beads than Jenny. After Maia used 144 beads to make a necklace, she had 5 times as many beads as Jenny. A) ho
tester [12383]

Answer:

A) Maia had 1920 beads more.

B) Maia had 2544 beads at first.

Step-by-step analysis:

Let x denote the beads with Jenny and y for Maia.

The information provided states that Maia possesses 2064 beads more than Jenny, which can be represented mathematically as:

y=x+2064...(1)

Additionally, after Maia made a necklace with 144 beads, she had five times more beads than Jenny.

This can also be formulated as an equation:

y-144=5x...(2)

A) Since Maia had 2064 beads more than Jenny before using 144 beads, we calculate her final bead count by subtracting 144 from 2064.

\text{Number of beads Maia had more than Jenny in the end}=2064-144

\text{Number of beads Maia had more than Jenny in the end}=1920

Thus, Maia is left with 1920 beads more than Jenny.

B) To solve this system of linear equations, we will utilize the substitution method.

By inserting equation (1) into equation (2), we arrive at:

x+2064-144=5x

x+1920=5x

x-x+1920=5x-x

1920=4x

Now, let's divide our equation by 4.

\frac{1920}{4}=\frac{4x}{4}

480=x

Now, we'll substitute x=480 into equation (1) to isolate y.

y=480+2064

y=2544

Conclusively, Maia initially had 2544 beads.

3 0
3 months ago
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