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deff fn
2 months ago
15

answer to three friends each create 4 bags of starter bread dough. after ten days, each of those four bags is then divided into

four more bags of dough. how many days pass before 192 bags of dough are created
Mathematics
1 answer:
tester [12.3K]2 months ago
7 0
The solution is 20 days, found as follows:
Each of the three friends initially makes 4 bags of dough. After 10 days, each of these bags is split into 4 new bags:
3 friends × 4 bags = 12 bags, and 12 bags × 4 = 48 bags
Then in the following 10 days, 48 bags are again divided into 4 bags each:
48 × 4 = 192 bags
Adding the periods: 10 days + 10 days = 20 days
Therefore, 192 bags are created after 20 days.
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Axline Computers manufactures personal computers at two plants, one in Texas and the other in Hawaii. The Texas plant has 40 emp
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Answer:

a) The likelihood that none of the sampled employees are from the Hawaii plant is 1.74%.

b) The chance that exactly 1 employee from the sample is found working in the Hawaii plant is 8.70%.

c) There is an 89.56% chance that 2 or more employees in the sample are from the Hawaii plant.

d) The probability that 9 employees from the sample are working at the Texas plant is 8.70%.

Step-by-step explanation:

Each employee has two potential employment locations: either Texas or Hawaii. Thus, the binomial probability distribution can be utilized to solve this scenario.

Binomial probability distribution

This distribution defines the probability of achieving exactly x successes in n trials where there are only two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

Here, C_{n,x} denotes the number of ways to choose x objects from a set of n, represented by the subsequent formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of success occurring.

In this context, we know:

The sample comprises 10 employees, therefore n = 10.

a. Calculate the probability that none of the sampled employees are from the Hawaii plant (to 4 decimals)?

Given that 20 out of 60 employees are based in Hawaii:

p = \frac{20}{60} = 0.333

We aim to find P(X = 0).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.333)^{0}.(0.667)^{10} = 0.0174

Thus, the likelihood that none in the sample are from Hawaii stands at 1.74%.

b. Calculate the probability that 1 employee from the sample is from the Hawaii plant?

This is represented as P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{10,1}.(0.333)^{1}.(0.667)^{9} = 0.0870

Therefore, there is an 8.70% possibility that 1 employee in the sample comes from Hawaii.

c. Calculate the probability that 2 or more employees in the sample are from the Hawaii plant?

We can observe two scenarios: either fewer than 2 employees are from Hawaii or 2 and beyond. The combined probabilities equal decimal 1. So:

P(X < 2) + P(X \geq 2) = 1

We seek to find P(X \geq 2).

P(X \geq 2) = 1 - P(X < 2)

From problems a and b, we possess values for both probabilities.

P(X < 2) = P(X = 0) + P(X = 1) = 0.0174 + 0.0870 = 0.1044

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.1044 = 0.8956

Accordingly, the chance that 2 or more employees in this sample operate at the Hawaii plant is 89.56%.

d. Calculate the likelihood that 9 employees in the sample are working at the Texas plant?

This corresponds to the probability found in part b for 1 employee working in Hawaii.

Consequently, there is an 8.70% chance that 9 employees belong to the Texas plant.

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120 divided by 8 equals 15 inches for each segment.

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