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k0ka
6 days ago
8

Suppose a change of coordinates T:R2→R2 from the uv-plane to the xy-plane is given by x=e−2ucos(5v), y=e−2usin(5v). Find the abs

olute value of the determinant of the Jacobian for this change of coordinates.

Mathematics
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A man purchased 6 fruits at Rs 10 How many fruits will he sell at Rs 9 so that he may make an overall profit of 8%
Svet_ta [12734]

Response:

Detailed breakdown:

P(x)=S(x)-C(x)

0.8=9-C(x)

C(x)=9 -0.08

C(x)=8.92

3 0
1 month ago
You are painting a room. After 18 minutes, 64% of the room still needs painted. How long does it take to paint the entire room?
lawyer [12517]

Answer:

A) The total duration needed to paint the room is 50 minutes.

B) To paint 64% of the room takes 32 minutes.

Step-by-step explanation:

Given as:

After 18 minutes, 64% of the room still requires painting.

Therefore, within 18 minutes, (100% - 64% = 36%) of the room has been painted

Let T minutes be the total time required to paint the entire room.

Now, according to the question

A ) Using the unitary method

∵ In total, 36% of the room is covered in 18 minutes

Thus, in total time of \dfrac{18}{36} minutes, 1% of the complete room is painted.Consequently, 100% of the room would be painted in \dfrac{18}{36} × 100 minutes

i.e T = \dfrac{18\times 100}{36}

Thus, T = 50 min

Therefore, the duration needed to paint the entire room = T = 50 minutes

Thus, the time required to finish painting the entire room is 50 minutes. Answer

B) Again

Time taken to paint 64% of the room = x minutes

∵ 36% of the room has been painted in a total of 18 minutes

Thus, 1% of the entire room gets painted in \dfrac{18}{36} minutes

Consequently, painting 64% of the room will take \dfrac{18}{36} × 64 minutes

i.e x = \dfrac{18\times 64}{36}

Thus, x = 32 min

Therefore, the required time for painting 64% of the entire room = x = 32 minutes

Thus, the time required to paint 64% of the room amounts to 32 minutes. Answer

5 0
1 month ago
Jackson is conducting an experiment for his Physics class. He attaches a weight to the bottom of a metal spring. He then pulls t
zzz [12365]
The behavior of the spring can be described using either a sine or cosine function. The spring's maximum displacement is 6 inches, occurring at t=0, which we will define as the positive peak. Therefore, we can express the function as:
6sin(at+B). The spring's period is 4 minutes, which means the time factor in the equation must complete a cycle (2π) in 4 minutes. This gives us the equation 4min*a=2π, leading to a=π/2. Generally, a=2π/T where a is the coefficient and T is the period. For B, since sin(π/2)=1, we determine B=π/2 because at t=0, the equation becomes 6sin(B)=6. Therefore, we substitute to form f(t)=6sin(πt/2+π/2)=6cos(πt/2)
due to trigonometric relations.
7 0
2 months ago
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An elevator in a hotel moves at 20 feet per second. leaving from the ground floor, its height in feet after t seconds is given b
Inessa [12570]
After 7.5 seconds, the height will be 0
8 0
1 month ago
Select all the sequences of reflections that produce an image equivalent to the image r(180°, O)(△BCD).
tester [12383]

Answer:

The operation r(180°,0) represents a 180° rotation around the origin.

This rotation shifts our shape to the opposite quadrant (effectively translating it across two quadrants).

Thus, this can be seen as:

A reflection across the x-axis followed by a reflection across the y-axis.

Alternatively.

It can also be depicted as a reflection across the y-axis followed by a reflection across the x-axis.

There exists another reflection method, contingent upon the position of our figure.

When the figure is situated in either the first or third quadrant, reflecting over the line y = -x yields a result equivalent to the rotation.

Conversely, if the figure lies in the second or third quadrant, reflecting over the line y = x corresponds to the rotation.

We can merge these two approaches into a single expression:

A reflection over the line y = (-1)^n*x.

Here, n indicates the number identifying the quadrant containing the figure.

8 0
1 month ago
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