How do you convert 2.314 (14 repeating) as a fraction?

Alejandro wants to determine the average shoe size of all of the male students in his school. Which sample is likely to yield th

Svet_ta [12734]

B. every member of the boys' basketball team, as basketball players are typically taller, resulting in larger feet which do not accurately reflect the average shoe size of the male students.

5 0

1 month ago

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What are the eight-digit grid coordinates for benchmark 86 (circled in red)?

lawyer [12517]

Answer:

An eight-digit grid coordinate allows for precision within 10 meters.

Step-by-step explanation:

Grid coordinates are designed to direct accurately to a specific location by using a map that includes equally spaced vertical and horizontal lines, each assigned numbers to outline a place. The intersection of these vertical and horizontal lines has unique identifiers and creates small sections called grid squares.

The precision increases with the number of digits in the coordinate; an eight-digit designation gives accuracy to the nearest 10 meters.

3 0

2 months ago

A major department store chain is interested in estimating the mean amount its credit card customers spent on their first visit

Inessa [12570]

Answer: D) $\$50\pm\$11.08$

Step-by-step explanation:

Based on the provided information, we have

Sample size: n= 15

sample mean: $\overline{x}=\$50.50$

Sample standard deviation: s= $20

Since the population standard deviation is not known, we utilize a t-test.

For a significance level of 95% confidence: $\alpha=1-0.95=0.05$

Critical t-value : $t_{n-1, \alpha/2}=t_{014,0.025}=2.145$ [Using the Student's t-value table]

The required 95% confidence interval yields:-

$\overline{x}\pm t_{n-1, \alpha/2}\dfrac{s}{\sqrt{n}}\\\\ =\$50.50\pm(2.145)\dfrac{\$20}{\sqrt{15}}\\\\\approx \$50\pm\$11.08$

Thus, the sought-after 95% confidence interval for the mean amount spent by credit card customers during their initial visit to the new store in the mall, assuming normal distribution of the spending amounts, is:

$\$50\pm\$11.08$

5 0

2 months ago

The scatterplot below shows the shoe sizes of students and the number of books the students collected for the library book drive

zzz [12365]

Respuesta:

B. Generalmente, el tamaño del zapato de un estudiante no influye en la cantidad de libros recolectados.

Explicación paso a paso:

6 0

1 month ago

What other points are on the line of direct variation through (5, 12)? Check all that apply. (0, 0) (2.5, 6) (3, 10) (7.5, 18) (

Inessa [12570]

It is established that

A correlation between two variables, x and y, demonstrates a direct variation if it can be written in the format $y/x=k$ or $y=kx$

For this question, we have

the point $(5,12)$ lies on the direct variation line

therefore

Determine the constant of proportionality k

$y/x=k$ -------> substitute ------> $k=12/5$

The equation is

$y=\frac{12}{5}x$

Keep in mind that

If a point is located on the direct variation line

then

the point has to fulfill the direct variation equation

we will now validate each point

case A) point $(0,0)$

$x=0\ y=0$

Insert the values of x and y into the direct variation equation

$0=\frac{12}{5}*0$

$0=0$ -------> is valid

thus

the point $(0,0)$ lies on the direct variation line

case B) point $(2.5,6)$

$x=2.5\ y=6$

Insert the values of x and y into the direct variation equation

$6=\frac{12}{5}*2.5$

$6=6$ -------> is valid

thus

the point $(2.5,6)$ lies on the direct variation line

case C) point $(3,10)$

$x=3\ y=10$

Insert the values of x and y into the direct variation equation

$10=\frac{12}{5}*3$

$10=7.2$ -------> is not valid

thus

the point $(3,10)$ does not lie on the direct variation line

case D) point $(7.5,18)$

$x=7.5\ y=18$

Insert the values of x and y into the direct variation equation

$18=\frac{12}{5}*7.5$

$18=18$ -------> is valid

thus

the point $(7.5,18)$ lies on the direct variation line

case E) point $(12.5,24)$

$x=12.5\ y=24$

Insert the values of x and y into the direct variation equation

$24=\frac{12}{5}*12.5$

$18=30$ -------> is not valid

thus

the point $(12.5,24)$ does not lie on the direct variation line

case F) point $(15,36)$

$x=15\ y=36$

Insert the values of x and y into the direct variation equation

$36=\frac{12}{5}*15$

$36=36$ -------> is valid

thus

the point $(15,36)$ lies on the direct variation line

ultimately

the solution is

$(0,0)$

$(2.5,6)$

$(7.5,18)$

$(15,36)$

5 0

2 months ago

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