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marishachu
2 months ago
5

A soccer ball is kicked upward from a hill and then falls to the ground. The height, in feet, of the ball after t sec is modeled

by the function h(t) = –16t2 + 26t +12. What is the initial height of the ball?
Mathematics
2 answers:
lawyer [12.5K]2 months ago
8 0

Answer:

The result is 12 feet.

Step-by-step explanation:

Zina [12.3K]2 months ago
8 0

Answer: The ball starts at a height of 12 feet.

Step-by-step explanation:

The height(h) of the ball, measured in feet, after t seconds is modeled by the function h(t)=-16t^2+26t+12.

As height corresponds to time, we can determine that the ball's initial elevation occurs when:

t=0

To ascertain the starting height, substitute t=0 into the equation:

h(0)=-16(0)^2+26(0)+12\\\\h(0)=0+0+12\\\\h(0)=12

Thus, the ball's initial height is 12 feet.

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