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Reptile
17 days ago
5

Jacque needs to buy some pizzas for a party at her office. She's ordering from a restaurant that charges a \$7.50$7.50dollar sig

n, 7, point, 50 delivery fee and \$14$14dollar sign, 14 per pizza. She wants to buy as many pizzas as she can, and she also needs to keep the delivery fee plus the cost of the pizzas under \$60$60dollar sign, 60.
Each pizza is cut into 888 slices, and she wonders how many total slices she can afford.

Let PPP represent the number of pizzas that Jacque buys.

1) Which inequality describes this scenario?
Mathematics
1 answer:
Svet_ta [4.3K]17 days ago
5 0

Answer:

Step-by-step explanation:

Delivery charge = $7.50

Cost per pizza = $14

Budgeted total = $60

7.50 + 14p < 60

First, subtract 7.50 from both sides

14p < 60 - 7.50

14p < 52.50

Now divide both sides by 14

p < 52.50 / 14

p < 3.75

Each pizza consists of 8 slices

Therefore, the total number of slices she can buy = 3.75 × 8

= 30 slices

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Which statement is true about the discontinuities of the function f(x)? F (x) = StartFraction x minus 5 Over 3 x squared minus 1
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Question:

Which statement is accurate concerning the function’s discontinuities f(x) = \frac{x-5}{3x^2-17x-28}

A) There are gaps at x = 7 and.

B) Asymptotes exist at x = 7 and.

C) Asymptotes exist at x = –7 and.

D) Gaps are present at (–7, 0) and.

Answer:

B) Asymptotes exist at x = 7 and (x = \frac{-4}{3})

Step-by-step explanation:

Given:

f(x) = \frac{x-5}{3x^2-17x-28}

Goal:

Identify the correct statement

f(x) = \frac{x-5}{3x^2-17x-28}

We need to factor the denominator first.

f(x) = \frac{x-5}{(3x+4)(x-7)}

To express x in terms of (3x+4) and (x-7):

3x + 4 =

3x = -4

Divide both sides by 3:

x = \frac{-4}{3}

x - 7

x = 7

Next, evaluate the limit when (x = \frac{-4}{3}) and at (x = 7)

lim f(x) as (x = \frac{-4}{3}) = ±∞

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Since both scenarios result in the denominator approaching zero, they represent asymptotes.

Thus, asymptotes are found at (x = \frac{-4}{3}) and x=7

Option B is determined to be correct

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