Question 1
Total budget sums up to 180 + 475 + 15 + 50 + 65 + 25 + 150 + 30 = $990.
Actual expenditure amounts to 182 + 475 + 12 + 65 + 68 + 12.50 + 150 + 36 = $1000.5.
Mae Green surpassed her designated budget.
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Question 2
Eleanor:
Earned = 380.48
Spent = 16.50
Peter:
Earned = 120 + 13.65 + 100 = 233.65.
Combined total income = 233.65 + 380.48 - 16.50 = 597.63.
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Question 3
Aggregate expenditure = 540 + 48.55 + 34.15 + 12.80 + 18.95 + 38.60 + 2 + 6.50 = 701.55.
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Question 4
Marie's updated balance = 250.65 - [21.95+48.50+75.60] + 55 = $159.50.
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Question 5
[235/825] × 100 = 28.48%
Answer:
a) The first inequality is 100 + 55x > 150 + 51x;
b) The final inequality results in x > 12.5
c) Sal's mother will need to use the second phone for at least 13 months.
Step-by-step explanation:
a) Let x represent the number of months.
1. The first phone is priced at $100, with a monthly fee of $55 for unlimited use, leading to a total cost of $(100 + 55x) for x months.
2. The second phone costs $150 with a monthly fee of $51 for unlimited use, resulting in a total of $(150 + 51x) for x months.
3. For the second phone to be cheaper, we set up the inequality:
150 + 51x < 100 + 55x
which simplifies to
100 + 55x > 150 + 51x
b) Now solve this:
55x - 51x > 150 - 100
4x > 50
so x > 12.5
c) This means Sal's mother has to retain the second phone for at least 13 months (since x > 12.5).
B. f(x) ≤ 0 over the interval [0, 2]. D. f(x) > 0 over the interval (–2, 0). E. f(x) ≥ 0 over the interval [2, ).
For lines that are perpendicular, their slopes are negative reciprocals. For instance, if line a’s slope is 2/3, then line b must have a slope of -3/2.