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koban
1 month ago
13

Work out the percentage change to 2 decimal places when a price of £57.99 is decreased to £49.99.

Mathematics
1 answer:
Inessa [12.5K]1 month ago
5 0
Percentage change in price = 13.80%.
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What is the logarithm of the equilibrium constant, log K, at 25°C of the voltaic cell constructed from the following two half-re
lawyer [12517]

Answer:

4.0921 reflects the logarithm of the equilibrium constant.

Step-by-step explanation:

Fe^{2+} (aq) +2e^{-}\rightarrow Fe(s); ​E​° = - 0.41 V

Ag^+(aq) + e^-\rightarrow Ag(s); E° = 0.80 V

Iron has a negative reduction potential, indicating its tendency to lose electrons and undergo oxidation, and thus it will be at the anode.

E^{o}_{cell}=Reduction potential of cathode - Reduction potential of anode

E^{o}_{cell}=E^{o}_c-E^{o}_a

=0.80 V-(-0.41 V)=1.21 V

Fe^{2+} (aq) + 2e^{-}\rightarrow Fe(s); ​E​° = - 0.41 V

2Ag^+(aq) + 2e^-\rightarrow 2Ag(s); E° = 0.80 V

Net reaction: Fe(s)+2Ag^{+}\rightarrow Fe^{2+}+2Ag(s)

n = 2

To determine the equilibrium constant, we utilize the correlation with Gibbs free energy, as follows:

\Delta G^o=-nfE^o_{cell}

and,

\Delta G^o=-RT\ln K_{eq}

Aligning these two equations yields:

nfE^o_{cell}=RT\ln K_{eq}

where,

n = electrons transferred = 2

F = Faraday's constant = 96500 C

E^o_{cell} = standard electrode potential of the cell = 1.21 V

R = gas constant = 8.314 J/K.mol

T = reaction temperature = 25^oC=[273+25]=298K

Substituting values into the equation, we arrive at:

2\times 96500\times 1.21 V=8.314\times 298\times \ln K_{eq}

\ln K_{eq}=9.3478

\log K_{eq}=\frac{9.3478}{2.303}=4.0921

4.0921 represents the logarithm of the equilibrium constant.

7 0
2 months ago
A ship anchored in a port has a ladder which hangs over the side. The length of the ladder is 200cm, the distance between each r
Leona [12618]

Response:

The answer to the inquiry is 8 hours.

Step-by-step breakdown:

Information

Ladder length = 200 cm

Distance between rungs = 20 cm

Tide rise rate = 10 cm/h

Fifth rung =?

Procedure

1.- Determine the total height the tide must reach

Height = 20 cm x 4

                 = 80 cm   as the first rung is touching the water.

2.- Calculate the time needed

Rate = distance / time

-Solve for time

Time = distance / rate

-Substitute values

Time = 80 cm / 10 cm/h

-Final outcome

Time = 8 hours.

3 0
2 months ago
What’s the answer ?
AnnZ [12381]
The correct answer is D
4 0
1 month ago
Read 2 more answers
555 grams of wool were needed to knit a sweater, a hat, and a scarf. The hat required 5 times less wool than the sweater and 5 g
Zina [12379]

Answer:

The amount of wool required for a sweater was 400 grams.

A hat needed 80 grams of wool.

A scarf required 75 grams of wool.

Step-by-step explanation:

Let

x ------> grams of wool necessary for a sweater

y -----> grams of wool necessary for a hat

z -----> grams of wool necessary for a scarf

From the information given

x+y+z=555 -----> equation A

y=x/5 ----> x=5y -----> equation B

y=z+5 ---> z=y-5 ----> equation C

By substituting equations B and C into equation A, we can solve for y:

(5y)+y+(y-5)=555

7y=560

y=80 grams

Now, find x

x=5(80)=400 grams

Next, determine z

z=80-5=75 grams

In conclusion,

400 grams of wool was required for the sweater,

the hat needed 80 grams of wool, and

the scarf required 75 grams of wool.

4 0
3 months ago
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