6 pints of a 20 percent solution of alcohol in water are mixed with 4 pints of a 10 percent alcohol in water solution. The perce

Question

Len

2 months ago

9

6 pints of a 20 percent solution of alcohol in water are mixed with 4 pints of a 10 percent alcohol in water solution. The perce

ntage alcohol in the new solution is
A. 16
B. 15
C. 14
D. 13
E. 12
am I correct by saying 15?

Mathematics

2 answers:

Inessa [12.5K] · Answer 1 · 2026-03-20T23:56:14+03:00

Inessa [12.5K]2 months ago

4 0

Total Volume equals 6 + 4 = 10 pints
Let’s find the amount of alcohol in the final solution:
20% of 6 yields 1.2 pints
10% of 4 gives.4 pints
Totaling 1.6 pints of alcohol in 10
Percentage = (1.6/10) * 100 = 16 percent.
the answer is A

Leona [12.6K] · Answer 2 · 2026-03-20T23:59:26+03:00

The alcohol percentage in the final mixture is: 16%(A)

Further clarification

Concentration can be quantified in various forms like moles, percent (% weight/volume), molarity, molality, parts per million (ppm), or mole fraction. It indicates the quantity of solute in a specified volume of solvent.

Molarity (M)

Molarity represents the number of moles of solute present in every 1 liter of solution.

$\large {\boxed {\bold {M ~ = ~ \frac {n} {V}}}$

Where

M = Molarity

n = Number of moles of solute

V = volume of the solution

COMBINING SOLUTIONS

Molarity of the combined solutions:

Vm Mm = V1. M1 + V2. M2

Thus:

$\displaystyle Mm =\frac{V1.M1+V2.M2}{Vm}$

where:

Mm = Combined molarity (M)

Vm = V1 + V2 = total volume (ml)

In this case,

6 pints of a 20 percent alcohol solution in water are combined with 4 pints of a 10 percent alcohol solution in water.

V1=6 pints = 2.83906 liters, and the concentration M1 =20% = 0.2

V2=4 pints = 1.89271 liters, M2=10% = 0.1

Vm = 2.83906 + 1.89271 = 4.73177 Liters

$\displaystyle Mm=\frac{V1.M1+V2.M2}{Vc}\\\\Mm=\frac{2.83906.0.2+1.89271.0.1}{4.73177}\\\\Mm=0.16=16\%$

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Keywords: molarity, alcohol solution,mixed solution,pints