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Setler79
3 months ago
15

Jillian’s school is selling tickets for a play. The tickets cost $10.50 for adults and $3.75 for students. The ticket sales for

opening night totaled $2071.50. The equation 10.50 a plus 3.75 b equals 2071.50, where a is the number of adult tickets sold and b is the number of student tickets sold, can be used to find the number of adult and student tickets. If 82 students attended, how may adult tickets were sold?
Mathematics
2 answers:
Zina [12.3K]3 months ago
8 0

Answer:

The number of adult tickets sold is 168.

Step-by-step explanation:

* Here's the solution approach:

- Adult ticket price: $10.50

- Student ticket price: $3.75

- Total revenue from opening night tickets: $2071.50

- Equation representing total revenue:

 10.50 a + 3.75 b = 2071.50, where a = number of adult tickets and b = number of student tickets.

- Number of students who attended: 82

* Solving the problem:

Since the number of students is 82, b = 82

Substitute into the equation:

10.50 a + 3.75 × 82 = 2071.50

Calculate 3.75 × 82 = 307.5

The equation becomes:

10.50 a + 307.5 = 2071.50

Subtract 307.5 from both sides:

10.50 a = 1764

Divide both sides by 10.50:

a = 1764 / 10.50 = 168

Therefore, 168 adult tickets were sold.

Zina [12.3K]3 months ago
8 0

Answer:

168

Step-by-step explanation:

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