Let’s determine the actual mean
First, we sum all the values
87+46+90+78+89 = 390
Then, we divide 390 by the count of numbers present.
390/5 = 78
Thus, the mean is 78
Emi did not manage to calculate the difference
B. f(x) ≤ 0 over the interval [0, 2]. D. f(x) > 0 over the interval (–2, 0). E. f(x) ≥ 0 over the interval [2, ).
Initially, we must determine the median from the provided dataset. To achieve this, we need to sort the values:
12, 15, 18, 20, 23, 23, 28
Thus, the median appears to be 20
To ensure the median remains unchanged, the eighth hour would need to have 20 visitors, allowing the revised dataset to be:
12, 15, 18, 20, 20, 23, 23, 28
I hope this clarifies things!
During an archaeological excavation, an ancient campfire is uncovered. The charcoal is determined to have significantly less than 1/1000 of the standard amount of 
. Calculate the minimal age of the charcoal, taking into account that 
Response:
57300 years
Step-by-step breakdown:
Using the relationship of half-life time against fraction, which can be expressed as:
In this context,
N indicates the current atom
represents the initial atom
t signifies the time
denotes the half-life
Since the charcoal was found to contain less than 1/1000 of the typical amount of
.
Thus;
However; the objective is to estimate the minimum age of the charcoal while noting
this means , then:
If
Then
Consequently, it can be estimated that the minimum time elapsed is 10 half-lives.
For , the standard half-life time is 5730 years
Thus, the estimation of the minimum age of the charcoal is 5730 years × 10
= 57300 years
1/ 816
Step-by-step explanation:
Step 1 :
Assumptions made
Number of students in the school = 18
Number selected randomly = 3
Step 2 :
Calculating number of ways to choose 3 students from a group of 18:
C(18,3) = 18! /(3!(18-3)!) = 18*17*16/3*2*1 = 816
Ways to choose the youngest 3 students = 1
Hence, the probability of picking the 3 youngest students from this group is 1/ C(18,3) = 1/ 816
