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Pepsi
1 month ago
12

A sprinter accelerates from rest to a velocity of 12m/s in the first 6 seconds of the 100 meter dash .

Physics
1 answer:
ValentinkaMS [3.4K]1 month ago
5 0
a) 36 m b) 64 m. Explanation: Given parameters are: initial velocity (v₀) = 0 m/s, final velocity (v) = 12 m/s, time (t) = 6 s. With the equation Δx = ½ (v + v₀) t, we find Δx to be 36 m. Since the track is 100 m, the sprinter must cover an additional 64 m.
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Ferns that eject spores generally do so in pairs, with two spores flying off in opposite directions. The structure from which th
Maru [3345]

Answer:

It eliminates recoil.

Explanation:

Every action has a corresponding reaction that is equal and opposite.

According to the conservation of momentum, when a single spore is released, the fern experiences a recoil that diminishes the energy and velocity of the spore. However, by ejecting the spores in pairs, the recoil is neutralized, allowing the entire energy to be imparted to the spores, which leads to increased launch speeds.

5 0
1 month ago
The energy gaps between the valence and conduction bands are called band gaps. For silicon, the band gap is 1.1 eV; for fused si
serg [3582]
I appreciate you bringing your question here. I trust this response will be beneficial. Don’t hesitate to reach out with additional queries.
<span>d) Infrared photons have insufficient energy to bridge the gap, which leads to only partial absorption, in contrast to how visible photons are entirely absorbed.</span>
6 0
1 month ago
Question 1
Keith_Richards [3271]

Answer:

1)  g = 4π² / m, 3) on the x-axis we have the pendulum lengths, while the y-axis shows the squared periods.

Explanation:

a) learners can model this system as a simple pendulum, where the angular velocity is given by

         w = √ g / l

Here, angular velocity, frequency, and period are interconnected:

         w = 2π f = 2π / T

Substituting yields:

         T = 2π√ l / g

Using this formula, students can calculate the gravitational acceleration by measuring the period for several pendulum lengths and plotting:

        T² = 4π²  l / g

We plot T² against l.

This represents a linear equation where T² is on the y-axis and l is on the x-axis:

        y = (4π² / g) l

The slope is given by:

         m = 4π² / g

Solving for g gives:

         g = 4π² / m

The slope is determined from the line's values rather than experimental data.

2) To perform the experiment, the string is secured to the sphere, then the pendulum length from the pivot to the sphere's center is measured using a tape measure. A slight angle (less than 10 degrees) is released, allowing the first swing to occur. Generally, the time for several oscillations, usually 10 or 20, is tracked to find the period:

    T = t / n

Next, a table is created comparing T² to the length, plotted with length on the x-axis to find the slope, from which the gravitational acceleration is derived.

3) The independent variable, which is the length of the pendulums, is plotted on the x-axis, while the dependent variable, the squared period, is on the y-axis.

4) Referring to the line equation:

            m = 4π² / g

             resulting in:

            g = 4π² / m

5) Once the spring is cut, the sphere continues to be influenced by gravitational acceleration. The harmonic motion ceases, and the sphere moves vertically.

5 0
2 months ago
A crate on a motorized cart starts from rest and moves with a constant eastward acceleration ofa= 2.60 m/s^2. A worker assists t
Keith_Richards [3271]

Response:

To find power, we must first determine the work done by the force.

1) We will use the following equation to calculate work:

\int\limits {F} \, dx

The force is provided by the problem; our goal is to express 'dx' in terms of 't'

2) It's known that:

\frac{dV}{dt} = a = 2.6

Thus, we have:

v = 2.6t

Then:

\frac{dx}{dt} = V = 2.6t\\ \\dx = 2.6t*dt

3) Finally, substituting all known values gives us:

\int\limits^{4.7}_{0} {5.4t*2.6t} \, dt

After some calculations, the resulting work is:

161.9638 J.

4) To find power, we will use the following equation:

P = \frac{W}{t}

Thus

P = 161.9638/4.7 = 34.46 W

8 0
1 month ago
A sphere of radius 0.03m has a point charge of q= 7.6 micro C located at it’s centre. Find the electric flux through it?
Sav [3153]

Answer:

The electric flux going through the sphere is 8.58 *10^{5} \frac{Nm^2}{C}

Explanation:

Given

Radius,\ r = 0.03m\\Charge,\ q =7.6\µC

Required

Calculate the electric flux

Electric flux can be computed using the formula;

Ф = q/ε

Where ε stands for the electric constant permittivity

ε = 8.8542 * 10^{-12}

Substituting ε = 8.8542 * 10^{-12} and q =7.6\µC; the formula simplifies to

Ф = \frac{7.6\µC}{8.8542 * 10^{-12}}

Ф = \frac{7.6 * 10^{-6}}{8.8542 * 10^{-12}}

Ф = \frac{7.6}{8.8542} *\frac{10^{-6}}{10^{-12}}

Ф = \frac{7.6}{8.8542} *10^{12-6}}

Ф = 0.85834970974 *10^{12-6}}

Ф = 0.85834970974 *10^{6}}

Ф = 8.5834970974 *10^{5}}

Ф = 8.58 *10^{5} \frac{Nm^2}{C}

Thus, the electric flux through the sphere is 8.58 *10^{5} \frac{Nm^2}{C}

7 0
2 months ago
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