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Pepsi
3 months ago
12

A sprinter accelerates from rest to a velocity of 12m/s in the first 6 seconds of the 100 meter dash .

Physics
1 answer:
ValentinkaMS [3.4K]3 months ago
5 0
a) 36 m b) 64 m. Explanation: Given parameters are: initial velocity (v₀) = 0 m/s, final velocity (v) = 12 m/s, time (t) = 6 s. With the equation Δx = ½ (v + v₀) t, we find Δx to be 36 m. Since the track is 100 m, the sprinter must cover an additional 64 m.
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