A car with an initial cost of $23,000 is decreasing in value at a rate of 8% each year. Write the exponential decay function des

The 99% confidence interval for the actual mean difference between average mail-order and internet purchase amounts falls within [$(-31.82), $12.02].

Step-by-step clarification:

We know a random sample of 16 mail-order sales receipts shows a mean sale amount of $74.50 and a standard deviation of $17.25.

For internet sales, a random sample of 9 receipts gives a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal value utilized for constructing a 99% confidence interval for the true mean difference is given by;

                      P.Q.  =  

 ~

where,

= sample mean of mail-order sales = $74.50

= sample mean of internet sales = $84.40

= standard deviation for mail-order sales = $17.25

= standard deviation for internet sales = $21.25

= number of mail-order sales receipts = 16

= number of internet sales receipts = 9

Furthermore,  

 =   = 18.74

The actual mean difference between average mail-order and internet purchases is denoted by (

).

Thus, the 99% confidence interval for () is expressed as;

      = Here, the t critical value at the 0.5% significance level with 23 degrees of freedom is 2.807.           =

          = [$-31.82, $12.02]

Therefore, the 99% confidence interval for the true mean difference between average mail-order and internet purchases is [$(-31.82), $12.02].

Is there meant to be an image?

Subtracting seven from sixteen results in nine
The solution is nine

Response:

8861: 9495

Detailed explanation:

The income ratio for the years 2001 to 2003:

53,166: 56,970

To simplify, divide both sides by 6:

8,861: 9,495

This can't be simplified further, so that is the final result!

8861: 9495

I hope this helps! Have a great day:)

Respuesta:

P = 2/7 = 0.2857 o 28.57%

Explicación paso a paso:

En primer lugar, sabemos que hay 15 bolas y necesitamos identificar cuáles son pares y superiores a 10.

Por lo tanto, debemos calcular inicialmente la probabilidad de que el número obtenido sea par.

Los números pares son 2, 4, 6, 8, 10, 12, 14

Contamos 7 números de 15 ---> P(B) = 7/15

De esos números, solo dos son mayores a 10, que son 12 y 14, así que: P(A|B) = 2/15

Para encontrar la probabilidad de obtener un número par mayor que 10:

P(A/B) = P(A|B) / P(B)

P(A/B) = 2/15 / 7/15 = 2/7 = 0.2857

Para calcular el porcentaje: 0.2857 * 100 = 28.57%.